Answer:
x=3/2, y=6
Step-by-step explanation:
plz mark brainliest!
Answer:
it would be A
Step-by-step explanation:
Let
z-----------> t<span>he height of the larger box
x-----------> the length side of the box (smaller and larger box)
y-----------> t</span>he width side of the box (smaller and larger box)<span>
volume larger box=x*y*z
</span>volume smaller box=x*y*(0.80z)----> 0.80[x*y*z]
the difference in the volume of these two boxes=[x*y*z]*(1-0.80)
the difference in the volume of these two boxes=0.20*[x*y*z]
<span>The height of the smaller box is 12 in
</span>so
z*0.8=12--------> z=12/0.8---------> z=15 in
x=7 3/4 in--------> (7*4+3)/4---------> 31/4 in
y= 2 in
the difference in the volume of these two boxes=0.20*[(31/4)*2*15]
the difference in the volume of these two boxes=46.5 in³
the answer is
46.5 in³
Answer:
(upper left) 3 triangles
(upper right) 5 triangles
(lower left) 9 rectangles
(lower right) next pattern is a grid that is 8 by 8.
The pattern is the previous side multiplied by 2
first block is 1x1
second block is 2x2
third block is 4x4
next block would be 8x8
Step-by-step explanation:
Answer:
23 years
Step-by-step explanation:
Step 1: Calculate the rate constant (k) for the radioactive decay
A radioactive substance with initial concentration [A]₀ decays to 97% of its initial amount, that is, [A] = 0.97 [A]₀, after t = 1 year. Considering first-order kinetics, we can calculate the rate constant using the following expression.
ln [A]/[A]₀ = - k.t
k = ln [A]/[A]₀ / -t
k = ln 0.97 [A]₀/[A]₀ / -1 year
k = 0.03 year⁻¹
Step 2: Calculate the half-life of the substance
We will use the following expression.
= ln2/ k = ln 2 / 0.03 year⁻¹ = 23 years
