What's the answers to this question please?

Write a polynomial Of least degree With roots zero and -3

GuDViN [60]

Answer:

X^2+3x

Step-by-step explanation:

in order to get these roots, we would set up the equation to be (x)(x+3). We can then multiply it to get x^2+3x

3 0

3 years ago

Compare the values of the 2s and 5s in 55,220

Fed [463]

The value of the first 5 is 5 ten thousands and the second 5 i 5 thousands while the value of the first 2 is 2 hundreds and the second 2 is 2 tens.

4 0

3 years ago

Find a ratio equivalent to 15/60

Flauer [41]

Answer:

$\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}$

or

$\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}$

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

$\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots$

or

Multiply the numerator and the denominator by the same number:

$\dfrac{15}{60}\\\\=\dfrac{15\cdot2}{60\cdot2}=\dfrac{30}{120}\\\\=\dfrac{15\cdot3}{60\cdot3}=\dfrac{45}{180}\\\\=\dfrac{15\cdot4}{60\cdot4}=\dfrac{60}{240}\\\vdots$

7 0

3 years ago

Read 2 more answers

A farm has 15 rows of fruit trees with 7 trees in each row. The last 4 rows of trees are cherry trees. The remaining trees are o

siniylev [52]

Answer:

Total number of orange trees = 77 trees

Step-by-step explanation:

Given:

Total number of rows = 15

Total number of cherry rows = 4

Number of trees in each rows = 7

Find:

Total number of orange trees

Computation:

Total number of orange trees = [Total number of rows - Total number of cherry rows][Number of trees in each rows]

Total number of orange trees = [15 - 4]7

Total number of orange trees = [11]7

Total number of orange trees = 77 trees

6 0

3 years ago

Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0

4 years ago