21 times 100 divided by 70 =30
Answer:
Step-by-step explanation:
a.
first number is 1000-1+9=1008
9)1000(1
9
-------
10
9
-----
10
9
----
1
----
last number is 9999
9| 9999
---------
1111 |0
--------
9999=1008+(n-1)9
9999-1008=(n-1)9
n-1=8991/9=999
n=999+1=1000
b.
first digit=1000
last digit=9999-1=9998
2 |9999
---------
|4999|1
9998=1000+(n-1)2
(n-1)2=9998-1000=8998
n-1=4499
n=4499=1=5000
c.not sure
d.
total numbers=9000
9999=1000+(n-1)1
9999-1000=n-1
n=8999+1=9000
numbers divisible by 3=3000
first number=1002
last number=9999
9999=1002+(n-1)3
(n-1)3=9999-1002=8997
n-1=2999
n=2999+1=3000
numbers not divisible by 3=9000-3000=6000
e.
numbers divisible by 5=1800
first number=1000
last number=9995
9995=1000+(n-1)5
(n-1)5=9995-1000=8995
n-1=1799
n=1799+1=1800
numbers divisible by 7=1286
7 | 1000
---------
| 142-6
1000-6+7=1001
7 | 9999
|---------
1428-3
9999-3=9996
first digit=1001
last digit=9996
9996=1001+(n-1)7
(n-1)7=9996-1001=8995
n-1=1285
n=1285+1=1286
numbers divisible by 35=257
first digit=1015
35 ) 1000 ( 28
70
----
300
280
------
20
---
1000-20+35=1015
35)9999(285
70
----
299
280
-----
199
175
----
24
----
last digit=9999-24=9975
9975=1015+(n-1)35
(n-1)35=9975-1015=8960
n-1=8960/35=256
n=257
reqd. numbers=1800+1286-257=3019
You would make all the fractions have the same common denominator of 12. First you would keep the fraction 7/12 because the denominator is already 12. Next you would take the fraction 1/3 and multiply it by 4/4 and the new fraction for 1/3 becomes 4/12. Lastly you would take 2/3 and multiply that by 4/4 and the fraction becomes 8/12. Now you can compare the fractions with the same denominator. Therefore 7/12 is greater than 1/3 but less than 2/3
the perimeter is simply the sum of all its sides.
(6a+8)+(12a)+(6a+8)+(10a-4)
34a + 16 - 4
34a + 12.
Answer:
84°
Step-by-step explanation:
< DEB = ½× (31+ 137) = ½× (168) = 84°
