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2 years ago

Find the value of y A. 8√2 B. 4√2 C. 2√2 D. 4

Mathematics

1 answer:

11111nata11111 [884]2 years ago

8 0

Option b is the right answer

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How do you calculate 278 × 11 using estimation?<br>

neonofarm [45]

Answer:

2800

Step-by-step explanation:

round 278 to 280

then round 11 to 10

then times the 2 answers together

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2 years ago

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8^15÷8^−3 im lost i dont get this whole simply thing at all

Phantasy [73]

8^15 ÷ 1/8^3 = 8^15 x 8^3=8^18

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3 years ago

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A line passes through A(3, 7), and B(-4, 9). Find the value of a if C(a, 1) is on the line.

marissa [1.9K]

Answer:

ANSWER

a=-32

EXPLANATION

If C(a,1) is on the line that passes through A(3, 7), and B(-4, 9), then the three points are collinear.

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3 years ago

If a publisher of nontechnical books takes great pains to ensure that its books are free of typos, so that the probability of an

Troyanec [42]

Answer:

(a) 0.2707

(b) 0.8576

Step-by-step explanation:

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2 years ago

The city of Anvil is currently home to 21000 people, and the population has been growing at a continuous rate of 4% per year. Th

Yanka [14]

Answer:

They'll reach the same population in approximately 113.24 years.

Step-by-step explanation:

Since both population grows at an exponential rate, then their population over the years can be found as:

$\text{population}(t) = \text{population}(0)*(1 + \frac{r}{100})^t$

For the city of Anvil:

$\text{population anvil}(t) = 21000*(1.04)^t$

For the city of Brinker:

$\text{population brinker}(t) = 7000*(1.05)^t$

We need to find the value of "t" that satisfies:

$\text{population brinker}(t) = \text{population anvil}(t)\\21000*(1.04)^t = 7000*(1.05)^t\\ln[21000*(1.04)^t] = ln[7000*(1.05)^t]\\ln(21000) + t*ln(1.04) = ln(7000) + t*ln(1.05)\\9.952 + t*0.039 = 8.8536 + t*0.0487\\t*0.0487 - t*0.039 = 9.952 - 8.8536\\t*0.0097 = 1.0984\\t = \frac{1.0984}{0.0097}\\t = 113.24$

They'll reach the same population in approximately 113.24 years.

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3 years ago