Answer:
b. The current stays the same.
Explanation:
In the case given current is supplied by the battery to a bulb . Here, we should know that bulb also apply resistance to the flow of current .
Now, when an identical bulb is connected in parallel to the original bulb .
Therefore, both the resistance( bulb) are in parallel.
We know, when two resistance are in parallel , current through them is same and voltage is divided between them.
Therefore, in this case current stays same in the original bulb.
Hence, this is the required solution.
Answer:
C. 10⁻³ rads
Explanation:
Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:
θ = λ/a
where,
θ = angular resolution of Cat's eye = ?
λ = wavelength = 500 nm = 5 x 10⁻⁷ m
a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m
Therefore,
θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)
Therefore,
θ = 0.001
θ = Sin⁻¹(0.001)
θ = 0.001 rad = 1 x 10⁻³ rad
Hence, the correct answer is:
<u>C. 10⁻³ rads</u>
Answer:
B type ii supernova is the right answer
Approximately 0.4373 seconds
Speed of sound at 20 degree C is roughly 343 meters/second
Speed of light = 3x10^8 or 300,000,000 meters/second
at 150.0 feet away you set it up as:
150.0/343 - 150/3x10^8
150.0/343 = 0.43731778
150/3x10^8 = 5x10^-7 or 0.0000005
Subtract 0.43731778 - 0.0000005
Answer is 0.43731728
Rounding would be approx. 0.4373
Answer:
The velocity and height is 31 m/s and 44.4 m respectively .
Explanation:
Given :
Initial speed of rock , u = 8.5 m/s .
Time taken to reach ground , t = 2.25 s .
Also , acceleration due to gravity is , 
.
Now , to find the velocity when it hit ground .
Applying equation of motion :
Also , height from which rock is thrown is given by :
Hence , this is the required solution .
