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nordsb [41]
3 years ago
5

What is the maximum powr of a module in Watts to the nearest whole Watt?​

Physics
1 answer:
KonstantinChe [14]3 years ago
6 0

Complete question is;

You are looking at a module specification

sheet that has the table of information

below. What is the maximum power of this

module in Watts to the nearest whole Watt?

Value

Polycrystalline si

Characteristic

Cell Type

Cell

Configuration

Voc

160 in series

137.2 V

V_imp: 29.3 V

Ilsc: 8.60 A

I_Imp: 8.02 A

Dimensions (mm/in): 1000 x 1600 x 50 mm / 39.4" x 63" x 2"

Weight: 10 kg / 22 lbs​

Answer:

P ≈ 235 Watts

Explanation:

Formula for power is;

P = IV

Now, for maximum power, we will make use of I_imp and V_imp given

Thus, P = I_imp × V_imp

We are given;

V_imp: 29.3 V

I_Imp: 8.02 A

Thus: P = 8.02 × 29.3 = 234.986 Watts

We are to approximate to the nearest whole watt.

Thus: P ≈ 235 Watts

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Answer:

1.63366

Explanation:

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3 0
3 years ago
Which of the following is NOT a type of acceleration?
otez555 [7]
It’s C because just trust
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3 years ago
A composite material is to be designed with epoxy (Em 3.5 GPa) and unidirectional fibers. The longitudinal elastic modulus of th
LenKa [72]

Answer:

Minimum elastic modulus of fiber = 455.64 GPa

Explanation:

Contents of composite material = Epoxy and Unidirectional fibers

Elastic modulus of epoxy = 3.5 GPa

Elastic modulus of composite material = 320 GPa

Volume fraction of fiber = 70 %

Volume fraction of epoxy = 100 - 70 = 30%

Elastic modulus of composite material = 3.5 x 0.3 + Elastic modulus of fiber x 0.7 = 320

0.7 x Elastic modulus of fiber = 320 - 1.05 = 318.95

Elastic modulus of fiber = 455.64 GPa

Minimum elastic modulus of fiber = 455.64 GPa

5 0
3 years ago
Part complete during a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s
Inga [223]

The average force applied to the ball= 106.7 N

Explanation:

Force is given by

f= ΔP/t

ΔP= change in momentum= m Vf- m Vi

m= mass =0.2 kg

Vf= final velocity= 12 m/s

Vi=initial velocity= -20 m/s ( negative because it is going towards the wall which is treated as negative axis)

t= time= 60 ms= 0.06 s

now ΔP= 0.2 [ 12-(-20)]

ΔP=0.2 (32)=6.4 kg m/s

now force F= ΔP/t

F= 6.4/0.06

F=106.7 N

8 0
3 years ago
The reactive force developed by a jet engine to push an airplane forward is called thrust, and the thrust developed by the engin
finlep [7]

The value of the thrust developed by the engine of a boeing 777 in N and Kgf are ;

i) 376616N

ii) 38430Kgf

<h3>What is force?</h3>

Force is a push or a pull. The reactive force always serve to balance the applied force. We are here asked to convert the  the thrust developed by the engine of a boeing 777 which is about 85400 lbf to the following units;

i) N

ii)kgf

Thus;

1 Ib = 0.45 Kg

1 lbf = 0.45 Kg * 9.8 m/s^2 = 4.41 N

We know that;

1 lbf = 4.41 N

85400 lbf = 85400 lbf. * 4.41 N/1 lbf

= 376616N

Again;

1 lbf = 0.45 Kgf

85400 lbf = 85400 lbf * 0.45 Kgf/1 lbf

= 38430Kgf

Learn more about force:brainly.com/question/13191643

#SPJ1

3 0
1 year ago
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