
where:
F - force
m - mass
a - acceleration
We transform this formula to get a:

Answer:
7.59Ns
Explanation:
Given parameters:
Force = 1360N
Time of contact = 5.85 x 10⁻³s
Unknown:
Impulse = ?
Solution:
The impulse of the ball is given as:
Impulse = Force x time
Impulse = 1360 x 5.85 x 10⁻³ = 7.59Ns
Answer:
K.E = 30,000 J
Explanation:
Given,
The potential energy of the roller coaster car, P.E = 40000 J
The kinetic energy at height h/4, K.E = ?
According to the law of conservation of energy, the total energy of the system is conserved.
At height 'h', the total energy is,
P.E = mgh
K.E = 0
At height 'h/4', the total energy is
P.E + K.E = mgh
P.E = mgh/4
K.E = 1/2 mv²
Therefore,
mgh/4 + 1/2 mv² = mgh
gh/4 + v²/2 = gh
Hence,
v² = 3gh/2
Substituting in the K.E equation
K.E = 1/2 mv²
= 1/2 m (3gh/2)
= 3/4 mgh
= 3/4 x 40000
= 30000 J
Hence, the K.E of the roller coaster car is, K.E = 30000 J
Answer:
18 km
Explanation:
Convert km/h to m/s:
120 km/h × (1000 m/km) × (1 h / 3600 s) = 33.3 m/s
The time it takes the bomb to travel the 2000 meters is:
2000 m / (33.3 m/s) = 60 s
So it takes 60 seconds for the bomb to fall. The distance it fell is therefore:
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (0 m/s) (60 s) + ½ (10 m/s²) (60 s)²
Δy = 18,000 m
Δy = 18 km
Answer:106560 N
Explanation:
Given
Let Tension between 2 and 3 car be
and between 3 &4 is 

mass of freight car =37,000 kg
acceleration of car
is accelerating all freights behind 3
therefore


Thus

