A wheel of mass M and radius R rolls on a level surface without slipping. If the angular velocity of the wheel about its center
1 answer:
The most important thing you should remember in order to get how is its linear momentum relative to the surface is that the<span> point on the circumference is moving at w rad/second.
Therefore, here is the solving formulae:
if </span>
you can easily get <span> linear momentum p :
</span>
I'm sure that helps.
Therefore, here is the solving formulae:
if </span>
</span>
I'm sure that helps.
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Answer:
Explanation:
Since the pulley has a mass concentrated on its rim, the pulley can be considered as a ring.
The moment of inertia of a ring is
The mass on the left is heavier, that is the pulley is rotating counterclockwise.
By Newton's Second Law, the net torque is equal to moment of inertia times angular acceleration.
Here, the net torque is the sum of the weight on the left and the weight on the right.
Applying Newton's Second Law gives the angular acceleration
The relation between angular acceleration and linear acceleration is
Then, the linear acceleration of the masses is