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3 years ago

Please help i have a test and this is the only question im stuck on 30 points

Mathematics

1 answer:

tia_tia [17]3 years ago

4 0

It’s D because the line is on the positive side of the graph. The y-intercept is positive 5 and x-intercept is positive 4, which makes a slope of 5/4.

Hope this helped:)

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1. Solve. 6x + 10 = 22 2. Solve. 6x - 4 = 4x What is the answers

Diano4ka-milaya [45]

1) x= 2
6x2+10=22
2) x = 2
6x2-4=4x2

3 0

3 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

3 0

3 years ago

What is the range of the function of the graph

Alex_Xolod [135]

Answer : Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

GOOD LUCK

5 0

3 years ago

For online courses, like those in eCore, there is a positive correlation between the amount of time spent in the course and the

Troyanec [42]

Answer:

Regression Line is given by,

y = 22.909 + 0.209 x

The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436

Step-by-step explanation:

The equation of Regression equation is of the form of:

y = a + bx

where, a is intercept and b is slope

The formula for a and b is given by,

$a=\frac{\sum Y \sum X^2-\sum X \sum XY}{n\sum X^2-(\sum X)^2}\\ and, b = \frac{n\sum XY -\sum X \sum Y}{n\sum X^2-(\sum X)^2}$

Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72

Thus, a = 22.909

and b = 0.209

Thus, Regression Line is given by,

y = 22.909 + 0.209 x

Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436

Now plotting these line:

6 0

3 years ago

Solve each equation for given variable -5i -15 = 15

Illusion [34]

Answer:

i= -6

Step-by-step explanation:

-5i-15=15

if we use inverse operation here, it would be -5i=30, so i= -6

5 0

3 years ago

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