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a_sh-v [17]
3 years ago
6

Bryce ordered a set of beads. Of the beads he received, 17 were orange and 33 were a different color. What percentage of the bea

ds were orange? Write your answer using a percent sign (%). Will give brainliest.
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

id say around the 50 - 52 percent range

sorry if im wrong

brainly pls

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If f(x) = 5x − 1 and g(x) = 2x2 + 1, what is the value of (f × g)(-3)?
Softa [21]

f(x) = 5x − 1 and g(x) = 2x^2 + 1

(f × g)(x) =  (5x − 1)(2x^2 + 1)

(f × g)(x) = 10x^3 - 2x^2 + 5x - 1

Substitute x = - 3

(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1

(f × g)(-3) = 10(-27) - 2(9) -15 - 1

(f × g)(-3) =-270 - 18 - 16

(f × g)(-3) = -236

Answer

- 236

6 0
3 years ago
Each of five friends has between $3.50 and $4.25. Which could be the total amount of money the five friends have?
sleet_krkn [62]
The answer would be around $20
7 0
3 years ago
Read 2 more answers
CAN SOMEONE PLZZ HELP WIT THIS!!!!!
Shtirlitz [24]

Answer:

B

Step-by-step explanation:

b and a=40⁰ so if b+c is supplementary they equal 180⁰ together so 180-40= 150⁰

6 0
2 years ago
Read 2 more answers
Which equation represents this sentence?
emmainna [20.7K]
C: 7(-n) - 3 = n + 4
hope it helps!
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
2 years ago
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