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AleksandrR [38]
3 years ago
7

What is the value of x?

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0

Answer:

126°

Step-by-step explanation:

x = (87+165)/2

x = 252/2

x = 126

Answered by GAUTHMATH

Contact [7]3 years ago
6 0

Answer:

126

Step-by-step explanation:

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KatRina [158]

Answer:

30-100

28-100

25-100

7-100

Step-by-step explanation:

It's hard to explain but I try

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3 years ago
Find the outputs.. please help
morpeh [17]

Answer:

see below

Step-by-step explanation:

The steps are +2 then *4 then -8 then ÷2

Input  is 5

5 +2 =7 *4 = 28-8 = 20 ÷2 = 10     Output is 10

Input  is 9

9 +2 =11 *4 = 44-8 = 36 ÷2 = 18     Output is 18

Input  is 14

14 +2 =16 *4 = 64-8 = 56 ÷2 = 28     Output is 28

Input  is 18

18 +2 =20 *4 = 80-8 = 72 ÷2 = 36     Output is 36

Input  is 23

23 +2 =25 *4 = 100-8 = 92 ÷2 = 46     Output is 46

Input  is 7.5

7.5 +2 =9.5 *4 = 38-8 = 30 ÷2 = 20     Output is 20

Input  is 11.54

11.54 +2 =13.54 *4 = 54.16-8 = 46.16 ÷2 = 23.08     Output is 23.08

6 0
3 years ago
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I would help but I'm really tired

6 0
3 years ago
5x when x=7 ......... NEED HELP
Gnoma [55]

Answer:

35

Step-by-step explanation:

5 x 7 = 35

5 0
4 years ago
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g A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is cha
leva [86]

Answer:

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.410-0.35}{\sqrt{0.385(1-0.385)(\frac{1}{1000}+\frac{1}{700})}}=2.502    

p_v =2*P(Z>2.502)= 0.0123    

Comparing the p value with the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportion analyzed is significantly different between the two groups at 5% of significance.    

Step-by-step explanation:

Data given and notation    

X_{1}=410 represent the number of people indicating that their financial security was more than fair for the recent year

X_{2}=245 represent the number of people indicating that their financial security was more than fair for the year before

n_{1}=1000 sample 1 selected  

n_{2}=700 sample 2 selected  

p_{1}=\frac{410}{1000}=0.410 represent the proportion estimated of indicating that their financial security was more than fair this year

p_{2}=\frac{245}{700}=0.35 represent the proportion estimated of indicating that their financial security was more than fair the year before

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{410+245}{1000+700}=0.385  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.410-0.35}{\sqrt{0.385(1-0.385)(\frac{1}{1000}+\frac{1}{700})}}=2.502    

Statistical decision  

Since is a two sided test the p value would be:    

p_v =2*P(Z>2.502)= 0.0123    

Comparing the p value with the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportion analyzed is significantly different between the two groups at 5% of significance.    

7 0
3 years ago
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