Answer:
23.8 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:
150 g × (1 mol/166.00 g) = 0.904 mol
0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:
0.904 mol × (1 L/0.0380 mol) = 23.8 L
Chemistry. More specifically, analytical chemistry.
<span>Nitric acid is often manufactured from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming of natural gas, in a two-step process. In the first step, nitrogen and hydrogen react to form ammonia:
In the second step, ammonia and oxygen react to form nitric acid and water:</span>
The heat will flow from Cu to Fe because Cu has higher temperature and has lower peak value .
Given ,
two aircraft rivets , one iron and the other copper , are placed in a calorimeter .
the initial temp of the calorimeter is 20 degC .
mass of iron = 30 g
initial temp of iron = 0 degC
Mass of copper = 20 g
initial temp of copper = 100 degC
Here copper has higher temp ,thus heat flow from Cu to Fe .
<h3>
What is heat flow ?</h3>
Heat flow is the movement of heat from higher temperature to lower temperature .
<h3>What is calorimeter ?</h3>
It is an object used for measuring the heat flow , heat capacity of a chemical reaction as well as the physical changes .
Learn more about calorimeter here :
brainly.com/question/1407669
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Answer:
Volume of the sulfuric acid (25cm³), same mass of each metal (1g)
Explanation:
In an experiment, the CONTROL VARIABLE also known as constant is the variable that is kept unchanged for all groups in an experiment. This is done in order not to influence the outcome of the experiment.
In this case, students are trying to investigate the reactivity of four different metals. They added 1 g of each metal to 25cm³ of sulfuric acid and recorded the temperature change. Based on the explanation of control variable above, the VOLUME OF SULFURIC ACID (25cm³) and the MASS OF EACH METAL (1g) are the CONTROL VARIABLES because they are the same or unchanged in this experiment.
