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I am Lyosha [343]
1 year ago
12

Water and a nonpolar substance will need to be forcibly mixed. this best describes a(n):__________

Chemistry
1 answer:
Alex_Xolod [135]1 year ago
4 0

Water and a nonpolar substance will need to be forcibly mixed. this best describes a(n):__________

emulsion

What is emulsion?

a colloid system in which both the dispersed phase and the dispersion medium are liquids; a mixture of two immiscible liquids, one of which is scattered throughout the other in tiny droplets.

Emulsions include margarine, cold cream, and numerous medicinal ointments. Every time an emulsion is used, the container must be shaken since some emulsions have a tendency for the suspended particles to stick together and settle out.

Applied to a suitable foundation, a dehydrated gel emulsion of light- or radiation-sensitive silver halide is known as a film emulsion.

To learn more about Emulsion

brainly.com/question/6677364

#SPJ4

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The chemical reaction involving an acid and a base or alkali is know as a ​
saul85 [17]

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Neutralization reaction

Explanation:

The meaning is

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5 0
3 years ago
Read 2 more answers
If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the
Sedbober [7]

Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

7 0
3 years ago
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