1) mass composition
N: 30.45%
O: 69.55%
-----------
100.00%
2) molar composition
Divide each element by its atomic mass
N: 30.45 / 14.00 = 2.175 mol
O: 69.55 / 16.00 = 4.346875
4) Find the smallest molar proportion
Divide both by the smaller number
N: 2.175 / 2.175 = 1
O: 4.346875 / 2.175 = 1.999 = 2
5) Empirical formula: NO2
6) mass of the empirical formula
14.00 + 2 * 16.00 = 46.00 g
7) Find the number of moles of the gas using the equation pV = nRT
=> n = pV / RT = (775/760) atm * 0.389 l / (0.0821 atm*l /K*mol * 273.15K)
=> n = 0.01769 moles
8) Find molar mass
molar mass = mass in grams / number of moles = 1.63 g / 0.01769 mol = 92.14 g / mol
9) Find how many times the mass of the empirical formula is contained in the molar mass
92.14 / 46.00 = 2.00
10) Multiply the subscripts of the empirical formula by the number found in the previous step
=> N2O4
Answer: N2O4
Answer:
The product of aerobic respiration is Carbon dioxide.
Explanation:
- The process of breaking down glucose to produce energy and waste products is called respiration. Livings beings need respiration process to generate energy so that they can survive.
- The types of respiration are : Anaerobic and aerobic respiration.
- Aerobic respiration takes place in presence of oxygen and produces large amount of energy.
- The final product of aerobic respiration are carbon dioxide, water and 38 ATP of energy.
Answer:
The molar mass of
is 96.8 g/mol
Explanation:
The given molecular formula - 
Individual molar masses of each element in the compound is as follows.
Molar mass of nitrogen - 14.01 g/mol
Molar mass of of hydrogen = 1.008g/mol
Molar mass of carbon = 12.01 g/mol
Molar mass of oxygen =16.00 g/mol
Molar mass of
is
![2\times[1(14.01)+4(1.008)]+1(12.01)+3(16.00)= 96.8g/mol](https://tex.z-dn.net/?f=2%5Ctimes%5B1%2814.01%29%2B4%281.008%29%5D%2B1%2812.01%29%2B3%2816.00%29%3D%2096.8g%2Fmol)
Therefore,The molar mass of
is 96.8 g/mol