Match the term with its description.

1 answer:

7 0

Photosynthesis is The process that uses sunlight energy to convert water, and carbon dioxide into high energy glucose, and oxygen.

Chloroplast is This organelle of a cell, is where chlorophyll is found. The organelle most involved in photosynthesis.

Hope that helps!!! :)

Chlorophyll is a green pigment present in all plants, that absorbs light to provide energy for photosynthesis.

Energy is the ability to do work, That can produce physical changes within living, and non-living systems.

You might be interested in

What is the hyphen notation of nitrogen

vovikov84 [41]

N-16

7 protons & 9 neutrons
7 + 9 = 16

6 0

3 years ago

Trans-2-butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm−1); however, ir spectroscopy is

Elza [17]

However trans-2-Butene does not give a characteristic peak in 1620-1680 cm⁻¹ region but still the presence of carbon double bond carbon can be detected by detecting following peaks in IR Spectrum.

1) 3010-3100 cm⁻¹:
As in trans-2-Butene a hydrogen atoms ate attached to sp² hybridized carbon, therefore the stretching of =C-H (C-H) bond will give a peak of medium intensity in the range of 3010-3100 cm⁻¹.

2) 675-1000 cm⁻¹:
Another peak which is given by the bending of =C-H (C-H) bond with strong intensity will appear in the range of 675-1000 cm⁻¹.

3 0

3 years ago

List three differences between the earth 240 million years ago and the present earth.

raketka [301]

Dinosaurs, cavemen, sabertooth tiger

4 0

3 years ago

2) Calculate the percent composition of each element in Mgso,

iogann1982 [59]

Answer:

$\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%$

$\% Ag=93.1\%\\\\\% O=6.9\%$

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

$\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%$

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

$\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%$