39.58 and this is because the radius is half of the diameter so the diameter can be though of as 2r. The formula is C= 2pi r

We have, Discriminant formula for finding roots:

Here,
- x is the root of the equation.
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
1) Given,
3x^2 - 2x - 1
Finding the discriminant,
➝ D = b^2 - 4ac
➝ D = (-2)^2 - 4 × 3 × (-1)
➝ D = 4 - (-12)
➝ D = 4 + 12
➝ D = 16
2) Solving by using Bhaskar formula,
❒ p(x) = x^2 + 5x + 6 = 0



So here,

❒ p(x) = x^2 + 2x + 1 = 0



So here,

❒ p(x) = x^2 - x - 20 = 0



So here,

❒ p(x) = x^2 - 3x - 4 = 0



So here,

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Answer:
Step-by-step explanation:
y - y1 = m(x - x1) y1 = 1 x1 = 2 m = -1/3
y - 1 = -1/3(x - 2)
y = -x/3 + 2/3
12/66--->x/22
12/66--->4/22 (almost 4/20 if you know what I mean)
Answer:
A =4.5 m^2
Step-by-step explanation:
The area is found by
A = bh
The base is 2.5 and the height is 1.8
A = 2.5*1.8
A =4.5 m^2