2850*24/(4*24+18)
The light bulb consumes 600 watt-hours per day.
Answer:
ok
Step-by-step explanation:
Answer:
21 kWh
Step-by-step explanation:
1. Subtract 25% from the original amount.
25% of 28 kWh is ...
0.25 × 28 kWh = 7.00 kWh
Subtracting this from 28 kWh, we find the usage after reduction to be ...
28 kWh - 7 kWh = 21 kWh
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2. We know that if we reduce 100% of a quantity by 25%, then the resulting amount is (100 -25)% = 75% of the original. As a fraction, this is 75/100 = 3/4 of the original amount. Then the reduced usage is ...
(3/4) × (28 kWh) = 3·(7·4)/4 kWh = 3·7 kWh = 21 kWh
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Mario must reduce his usage to 21 kWh or less.
Answer:
x = ±i(√6 / 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
Imaginary root i
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2x² + 3 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
- [Division Property of Equality] Divide 2 on both sides: x² = -3/2
- [Equality Property] Square root both sides: x = ±√(-3/2)
- Simplify: x = ±i(√6 / 2)
