Answer:
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.
This means that 
Find the probability that one selected subcomponent is longer than 118 cm.
This is 1 subtracted by the pvalue of Z when X = 118. So



has a pvalue of 0.6443
1 - 0.6443 = 0.3557
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
Step-by-step explanation:
In order to find the length of side TS, first we need to find the length of side TR which is perpendicular to side QS.
By Geometric mean property:

Answer:
measure of two unknown angles are 35.7° and 75.4°
measure of one unknown side is 16.6 inches
Step-by-step explanation:
i used law of sines to find the angle opposite 10 inch side
sin 68.9/16 = sinФ/10
Ф = 35.7°
then is added 35.7 and 68.9 and subtracted the sum from 180° to get the measure of the third angle, 75.4°
i used law of sines again to find the measure of the third side
sin 68.9/16 = sin 75.4/x
x = 16.59
Answer:
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Step-by-step explanation: