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Lana71 [14]
3 years ago
15

Raul wants to buy a new collar for each of his 5 dogs. The collars come in a choice of 10 different colors. Step 1 of 2 : How ma

ny selections of collars for the 5 dogs are possible if repetitions of colors are allowed
Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

Answer:

100,000

Step-by-step explanation:

Calculation for How many selections of collars for the 5 dogs are possible if repetitions of colors are allowed

Based on the information given since he has 5 dogs that he want to purchase a collar for, which means that if the collar has 10 choice of variety of colors, then the selection of collars for the 5 dogs if repetitions of colors are allowed will be calculated as:

Selections of collars=10*10*10*10*10

Selections of collars=100,000

Therefore the numbers of selections of collars for the 5 dogs that are possible if repetitions of colors are allowed is 100,000

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The solution to given quadratic equation is x = -0.3851 or x = 10.3851

<em><u>Solution:</u></em>

Given equation is:

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To find: solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16

<u><em>Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,</em></u>

\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}

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