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4 years ago

A cube-shaped gift box has a volume of 8 cubic inches what is the side length of the box

Mathematics

2 answers:

mihalych1998 [28]4 years ago

6 0

V = s^3

8 = s^3

8 = 2^3

s=2 inches

larisa [96]4 years ago

3 0

Volume - S^3

8 - S^3

8 - 2^3

S -2 in

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PLEASE HELP ME! :(

snow_lady [41]

Here, I'll do the first one for you.
When they are talking about a number, use "x".
Since it says twice a number, you say 2x. Or 3x for three times the number
2x+12=3x-31
Then use algebra to find x. Get the numbers on one side and all the x's on the other.
2x+12+31=3x-31+31
2x+43-2x=3x-2x
x=43

Now do the rest on your own!

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3 years ago

Given centerB with m∠ABD = 95 degrees

kirill [66]

Answer:

It would be the fourth one to me Yw

Step-by-step explanation:

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3 years ago

Does anyone know this

Rudik [331]

Answer:

its the first one. you're right.

A reflection over y-axis.

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3 years ago

How do i add 567,890 567,096

marissa [1.9K]

567,890
+567,096
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1,134,986

3 0

3 years ago

According to the "January theory," if the stock market is up for the month of January, it will be up for the year. If it is down

PSYCHO15rus [73]

Answer:

The required probability is 0.031918.

Step-by-step explanation:

Consider the provided information.

It is given that According to an article in The Wall Street Journal, this theory held for 22 out of the last 34 years.

Therefore n=34

The probability it is either up or down is 0.5.

Thus the value of p =0.5 and q = 0.5

Now calculate the probability

Let X is the number of years that theory held.

X has a binomial distribution with n=34 and p=0.5

$P(X=22)=\binom{34}{22}(0.5)^{22}(0.5)^{12}\\P(X=22)=\frac{34!}{22!\times 12!}(0.5)^{22}(0.5)^{12}\\P(X=22)=548354040\times 5.8207660913\times 10^{11}\\P(X=22)=0.0319184060208\\P(X=22)\approx0.031918$

Hence, the required probability is 0.031918.

8 0

3 years ago