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NikAS [45]
3 years ago
7

4(x + 1) = 28 Multi step

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

x = 6

Step-by-step explanation:

Pardon the bad handwriting

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Destin walked 2km and Jane walked 4,000 ft. What is the approximate combined distance they walked? Note: 1 Foot (ft) is equal to
Anna11 [10]

Answer: Option C.

Step-by-step explanation:

The data is:

Destin walked 2km

Jane walked 4000ft.

Let's write both of those in the same units.

The data given is:

1ft = 0.0003048km.

and 4000ft is 4000 times that:

4000ft = 4000*1ft = 4000*0.0003048km = 1.22km

Then if we add those, we get:

Total distance = 2km + 1.22km = 3.22km

So we can already discard option D.

Now, we know that:

1km = 0.6214 miles.

then 3.22 km is 3.22 times that amount:

3.22km = 3.22*1km = 3.22*(0.6214 mi) = 2 miles

The correct option is C.

3 0
3 years ago
If you have a test average of 92 and a standard deviation of 1.8, you generally do well on tests.
MrRa [10]
Is that it is think it is 118
4 0
3 years ago
Read 2 more answers
The area of a rectangular park is 3/5 square mile. The length of the park is 7/8 mile. What is width of the park
Ira Lisetskai [31]
3/5 is 0.6
7/8 is 0.875
0.6/0.875 is 0.685714286
0.685714286 is 685714286/1000000000
(not so sure about it but that was what i came up with hope i helped)
6 0
3 years ago
Darsh’s simulated samples:
dusya [7]

Answer:

sample of 100 students

Step-by-step explanation:

The larger the sampl the more diverse your answers/ data will be.

4 0
3 years ago
Read 2 more answers
Find the exact value of csc theta if tan theta = sqrt3 and the terminal side of theta is in Quadrant III.
WARRIOR [948]

Answer:

3rd option

Step-by-step explanation:

Using the identities

cot x = \frac{1}{tanx}

csc² x = 1 + cot² x

Given

tanθ = \sqrt{3} , then cotθ = \frac{1}{\sqrt{3} }

csc²θ = 1 + (\frac{1}{\sqrt{3} } )² = 1 + \frac{1}{3} = \frac{4}{3}

cscθ = ± \sqrt{\frac{4}{3} } = ± \frac{2}{\sqrt{3} }

Since θ is in 3rd quadrant, then cscθ < 0

cscθ = - \frac{2}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = - \frac{2\sqrt{3} }{3}

8 0
3 years ago
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