Ask question

Ask question

All categories

3 years ago

13

the track has to meet certain specfications the largest angle, angle c is triple the smallest angle, angle B. Angle, A is double

the smallest angle, angle B all of the angles add to 180 degrees. create a equation to represent the sum of the angles ( using varaibles) and then solve for the varaibles to find the measure of the angles

1 answer:

Mila [183]3 years ago

6 0

Answer:

$\angle A=\mathbf{60^{\circ}}\\\angle B=\mathbf{30^{\circ}}\\\angle C=\mathbf{90^{\circ}}$

Step-by-step explanation:

Given

Angle C is triple that of angle B.

Angle A is double of angle B

Suppose the angle B is $x$

So, angle A and C are $2x$ and $3x$

$\angle A=2x$

$\angle B=x$

$\angle C=3x$

Add the angles A, B, and C to get $180^{\circ}$

$\Rightarrow \angle A+\angle B+\angle C=18^{\circ}\\\Rightarrow 2x+x+3x=180^{\circ}\\\Rightarrow 6x=180^{\circ}\\\Rightarrow x=30^{\circ}\\$

$\therefore \angle A=\mathbf{60^{\circ}}\\\angle B=\mathbf{30^{\circ}}\\\angle C=\mathbf{90^{\circ}}$

For more visit

https://brainly.in/question/1443350

You might be interested in

A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa

gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4 | red dice) = $\dfrac{1}{6}$

P (4 | green dice) = $\dfrac{3}{6}$ = $\dfrac{1}{2}$

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = $\dfrac{1}{2}$

The probability of two 1's and two 4's in the first dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^4$

= $\dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4$

= $6 \times ( \dfrac{1}{6})^4$

= $(\dfrac{1}{6})^3$

= $\dfrac{1}{216}$

The probability of two 1's and two 4's in the second dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $6 \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $( \dfrac{1}{6}) \times ( \dfrac{3}{6})^2$

= $\dfrac{9}{216}$

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = $\dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}$

The probability of two 1's and two 4's in both die = $\dfrac{1}{432} + \dfrac{1}{48}$

The probability of two 1's and two 4's in both die = $\dfrac{5}{216}$

By applying Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's ) = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's ) = $\dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}$

P(second die (green) | two 1's and two 4's ) = $\dfrac{0.5 \times 0.04166666667}{0.02314814815}$

P(second die (green) | two 1's and two 4's ) = 0.9

Thus; the probability the die chosen was green is 0.9

8 0

3 years ago

Selena was comparing the flying speeds of different birds in science class. Which of the three birds flies fastest? Why?

Mashcka [7]

Answer:

Option C. The robin flies fastest because its rate is 15 m/s

Step-by-step explanation:

Let

x -----> the time in seconds

y ----> the distance in meters

The speed is equal to divide the distance by the time

In this problem, the slope or unit rate of the linear equation is the same that the speed

<em>Robin's Flight</em>

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

take two points from the table

(2,30) and (3,45)

substitute in the formula

$m=\frac{45-30}{3-2}$

$m=\frac{15}{1}$

$m=15\frac{m}{sec}$

<em>Cardinal's Flight</em>

$y=10x$

$m=10\frac{m}{sec}$

<em>Blue Jay's Flight</em>

take two points from the graph

(0,0) and (2,20)

substitute in the formula

$m=\frac{20-0}{2-0}$

$m=\frac{20}{2}$

$m=10\frac{m}{sec}$

Compare

The robin flies fastest because its rate is 15 m/s

4 0

3 years ago

Addie bought lunch to go from a sandwich shop. She spent $12.00 for a $10.00 meal. What percent was the tip?

horsena [70]

Answer:

She gave a $2.00 tip witch would be %20 of her meal cost.

Step-by-step explanation:

</3 PureBeauty

4 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP I’LL GIVE BRAINLEST ITS ALEKS ALGEBRA 2 MATH

vlada-n [284]

A)
145 - 5d
5d = 145, set equal

29 days to lay all the track

b)
5*19 = 95

145-95 = 50

After 19 days, they have 50 miles to go.

4 0

2 years ago

Read 2 more answers

A group of eight golfers paid $430 to play a round of golf . Of the golfers one was a member and 7 were not what is the cost for

charle [14.2K]

Answer:

Incomplete question

Complete question;

A group of eight golfers paid $430 to play a round of golf . Of the golfers one was a member and 7 were not.

Another group of golfers consists of two members and one nonmember. They paid a total of $75. What is the cost for a member to play a round of golf, and what is the cost for a nonmember?

Answer: X = $82.695 for members

Y = $49.615 for non members

Step-by-step explanation:

Let's use X to denote members and Y for non-members.

Therefore, amount paid by one member to play + amount paid by 7 non-members to play = 430

X + 7Y = 430. . .1

Amount paid by 2 members to play + amount paid by one non-member to play = 215

2X + Y = 215. . .2

Solving both equations simultaneously

X+7Y = 430

2X +Y = 215

Therefore, from eqn 1. X = 430-7y

Substituting this into wan 2 gives

2(430-7Y) + Y = 215

860-14Y + Y = 215

860-215 =13Y

645 = 13y

Y = 49.615

Therefore substituting Y = 49.615 into any equation above

X + 7(49.615) = 430

X = 430-347.05

X = 82.695

3 0

3 years ago