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Pachacha [2.7K]
3 years ago
7

What’s is the approximate volume of the cone? Use 22/7 for pie.

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0

butter by bts

the only explanation for this worId

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In how many ways can we seat 3 pairs of siblings in a row of 7 chairs, so that nobody sits next to their sibling
monitta

Answer:

1,968

Step-by-step explanation:

Let x₁ and x₂, y₁ and y₂, and z₁ and z₂ represent the 3 pairs of siblings, and let;

Set X represent the set where the siblings x₁ and x₂ sit together

Set Y represent the set where the siblings y₁ and y₂ sit together

Set Z represent the set where the siblings z₁ and z₂ sit together

We have;

Where the three siblings don't sit together given as X^c∩Y^c∩Z^c

By set theory, we have;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | X^c \cup Y^c \cup Z^c  \right | =  \left | U  \right | - \left | X \cup Y \cup Z  \right |

\left | U  \right | - \left | X \cup Y \cup Z  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Therefore;

\left | X^c \cap Y^c \cap Z^c  \right | = \left | U  \right | - \left (\left | X \right | +  \left | Y\right | +  \left | Z\right | -  \left | X \cap Y\right | -  \left | X \cap Z\right | -  \left | Y\cap Z\right | +  \left | X \cap Y \cap Z\right | \right)

Where;

\left | U\right | = The number of ways the 3 pairs of siblings can sit on the 7 chairs = 7!

\left | X\right | = The number of ways x₁ and x₂ can sit together on the 7 chairs = 2 × 6!

\left | Y\right | = The number of ways y₁ and y₂ can sit together on the 7 chairs = 2 × 6!

\left | Z\right | = The number of ways z₁ and z₂ can sit together on the 7 chairs = 2 × 6!

\left | X \cap Y\right | = The number of ways x₁ and x₂ and y₁ and y₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Z\right | = The number of ways x₁ and x₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | Y \cap Z\right | = The number of ways y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 5!

\left | X \cap Y \cap Z\right | = The number of ways x₁ and x₂,  y₁ and y₂ and z₁ and z₂ can sit together on the 7 chairs = 2 × 2 × 2 × 4!

Therefore, we get;

\left | X^c \cap Y^c \cap Z^c  \right | = 7! - (2×6! + 2×6! + 2×6! - 2 × 2 × 5! - 2 × 2 × 5! - 2 × 2 × 5! + 2 × 2 × 2 × 4!)

\left | X^c \cap Y^c \cap Z^c  \right | = 5,040 - 3072 = 1,968

The number of ways where the three siblings don't sit together given as \left | X^c \cap Y^c \cap Z^c  \right |  = 1,968

5 0
3 years ago
Plz help! Big points!
Mama L [17]

Answer:

1209

Step-by-step explanation:

v= pi* r^2* h         r= d/2

soda:

d = 2    r = 1

h = 5

grabage:

d = 24   r = 12

h = 42

volume G: 19000.35

volume S: 15.71

volume G/ Volume S = # of soda cans

8 0
3 years ago
Find the difference of 2 3/8 - 5/8
vodka [1.7K]

Answer:1/8

Step-by-step explanation:

3 0
3 years ago
What is the arc measure of minor arc AB in degrees?
Ratling [72]

Answer:

m\widehat{AB} =55 \degree

Step-by-step explanation:

\because m\angle APC=m\angle DPE

(Vertical angles)

\therefore m\widehat {ABC} =m\widehat {DE}

(Measure of minor arc is equal to the measure of it's corresponding central angle)

\therefore m\widehat {AB}+m\widehat {BC} = m\widehat {DE}

\therefore m\widehat{AB} = m\widehat {DE} - m\widehat {BC}  \\  \\ m\widehat{AB} =93 \degree - 38 \degree \\  \\ m\widehat{AB} =55 \degree

3 0
3 years ago
Find an equation of the circle that has center (-4, 1) and passes through (3, -5)
Lemur [1.5K]

The general equation for a circle with center (a,b) and squared radius k is


(x-a)^2 + (y-b)^2 = k


Here we have


(x- - 4)^2 + (y -1)^2 = k


and the constant is fixed by substituting in the point we know (x,y)=(3,-5)


(x + 4)^2 + (y-1)^2 = (3+4)^2 + (-5-1)^2 = 85


Answer:


(x + 4)^2 + (y-1)^2 = 85


5 0
3 years ago
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