Answer:
For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.
Explanation:
Given data:
Mass of glucose = 10 g
Mass of oxygen required for complete combustion = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
Now we will convert the given mass of glucose into number of moles.
Number of moles = mass/ molar mass
Number of moles = 10 g/ 180.156 g/mol
Number of moles = 0.06 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
0.06 : 6×0.06 = 0.36 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Number of moles = 0.36 mol × 32 g/mol
Number of moles = 11.52 g
For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.
Answer:
According to the law of conservation of matter, the mixture should weigh 175 g
Explanation:
The law of conservation of matter is one of the basic guiding principles of chemical reactions.
It states that matter is neither created nor destroyed but can be converted from one form to another.
Although this law has been faulted with advances in science and technology, it is still found basically useful.
So applying the law to the question at hand, it is expected that all the mass of the sugar gets added to all the mass of the water
This brings the total mass to 25 + 150 = 175 grams
C, because liquids as gas can move on there own at different points but solids are locked in place and do not move past one another like liquids and gases do.
Answer: A. electrons are shared by many atoms and move freely