Question

A scuba diver releases a balloon containing 181 L of helium attached to a tray of artifacts at an underwater archaeological state. when the balloon reaches the surface, it has expanded to a volume of 351 L. The pressure at the surface is 1.00 atm. What is the pressure at underwater site? What is the depth of the underwater site Pressure increases by exactly 1.0 atm for every 10 m depth. At what depth was the diver working?

Answer 1

Answer:

1.94 atm is the pressure at underwater site.

19.4 meters is the depth of the underwater site.

Explanation:

Pressure of the balloon at the dept at which scuba diver is working:

= $P_1=?$

Volume of the balloon at the dept at which scuba diver is working:

= $V_1=181 L$

Pressure of the balloon at the surface:

= $P_2=1 atm$

Volume of the balloon at the dept at which scuba diver is working:

= $V_1=351 L$

Using Boyle's law:

$P_V_1=P_2V_2$ (at constant temperature)

$P_1=\frac{P_2V_2}{V_1}=\frac{1 atm\times 351 L}{181 L}=1.94 atm$

1.94 atm is the pressure at underwater site.

Pressure increases by exactly 1.0 atm for every 10 m depth.

Pressure increase for every 1 unit increase in depth= $\frac{1.0}{10}atm/m=0.1 atm/m$

Depth at which pressure is 1.94 atm  = h

$h\times 0.1 atm/m=1.94 atm$

$h=\frac{1.94 atm}{0.1 atm/m}=19.4 m$

19.4 meters is the depth of the underwater site.

Answer 2

The first step is to use the formula from Boyle's Law.
[(351 L)(1.0 atm)]/(181L) = 1.94 atm.
To determine the depth of the location where the diver was working, 1.94 is multiplied by 10. Therefore, the location of the underwater archaeological site is 19.4 meters below the surface.