For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.
From the problem, you know that 1) = 2.000 g.
Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).
1) = 5.022 g - 3.715 g = 1.307 g
Now you can complete our original task.
Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.
Answer:
C). 373 Kelvin, 100 degrees Celsius, 212 degrees Fahrenheit
Explanation:
Kelvin and Celsius are related using the equation K = C + 273.
Celsius and Fahrenheit are related using the equation F = (9/5) * C + 32.
This means that Kelvin and Celsius have to differ by 273, in which only B and C fit that description.
Then you can look at the Celsius and Fahrenheit readings from B and C and apply the equation F = (9/5) * C + 32. For B, you take 0 degrees Celsius and substitute it in for C to get F = (9/5) * 0 + 32, in which you get 32 degrees Fahrenheit and <em>not </em>the 212 degrees in answer B. For C, you do the same: F = (9/5) * 100 degrees Celsius + 32 = 212 degrees Fahrenheit, which does agree with the answer. Therefore, it must only be C.
In general, roots absorb phosphorus in the form of orthophosphate, but can also absorb certain forms of organic phosphorus. Phosphorus moves to the root surface through diffusion.
