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3 years ago

How did Rutherford discredit Thomson's plum pudding model of an atom?

Chemistry

2 answers:

Dafna1 [17]3 years ago

5 0

Answer:

He conducted an experiment using gold foil and alpha particles.

Explanation:

Ernest Rutherford in 1911 performed the gold foil experiment which provided a better outlook to the structure of the atom. In his experiment, he bombarded a thin gold foil with alpha particles. Most of the alpha particles passed through the gold foil and just a few was deflected back.

This observation led Rutherford to propose the nuclear model of the atom in which an atom has a small positively charged centre and electrons moving round it.

WARRIOR [948]3 years ago

4 0

Answer:

He conducted an experiment using gold foil and alpha particles.

Explanation:

In his experiment he use the alpha particles (which are positive) emitted by a radioactive element. If Thomson's plum pudding model was correct, the beam would go straight through the gold foil. But the alpha particles were deflected in all directions, some right back at the source. This suggest that the atom's positive charge was concentrated in a much tinier volume than Thomson imagined

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An experiment requires 40.0g of ethylene glycol, a liquid whose density is 1.114 g/mL. Rather than weigh the sample on a balance

uranmaximum [27]

Density= mass/volume
volume=mass/density
volume= 40.0g/1.114g per mL
volume= 35.90664273 mL
volume = 35.9 mL

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3 years ago

Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution i

alexdok [17]

Answer:

The value of dissociation constant of the monoprotic acid is $1.099\times 10^{-3}$ .

Explanation:

The pH of the solution = 2.46

$pH=-\log[H^+]$

$2.46=-\log[H^+]$

$[H^+]=0.003467 M$

$HA\rightleftharpoons H^++A^-$

Initially

0.0144 0 0

At equilibrium

(0.0144-x) x x

The expression if an dissociation constant is given by :

$K_a=\frac{[A^-][H^+]}{[HA]}$

$K_a=\frac{x\times x}{(0.0144-x)}$

$x=[H^+]=0.003467 M$

$K_a=\frac{0.003467 \times 0.003467 }{(0.0144-0.003467 )}$

$K_a=1.099\times 10^{-3}$

The value of dissociation constant of the monoprotic acid is $1.099\times 10^{-3}$ .

3 0

4 years ago

Would you like Brainliest?

lubasha [3.4K]

Answer:

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Explanation:

6 0

2 years ago

Read 2 more answers

What is the pressure in a 245 L tank that contains 5.21 kg of helium at 27 Celsius

Kitty [74]

<h2><u>Answer:</u></h2>

(These are not rounded to the correct decimal)

130.94 atm

13,266.6 kPa

99,571.4 mmHg

<h2><u>Explanation:</u></h2>

<u></u>

PV = nRT

V = 245L

P = ?

R = 0.08206 (atm) , 8.314 (kPa) , 62.4 (mmHg)

T = 273.15 + 27 = 300.15K

n = 1302.5 moles

How I found (n).

5.21kg x 1000g/1kg x 1 mole/4.0g = 1302.5 moles

Now, plug all the numbers into the equation.

Pressure in atm = (1302.5)(0.08206)(300.15) / 245 = 130.94 atm (not rounded to the correct decimal)

Pressure in kPa = (1302.5)(8.314)(300.15) / 245 = 13,266.6 kPa (not rounded to the correct decimal)

Pressure in mmHg = (1302.5)(62.4)(300.15) / 245 = 99,571.4 mmHg (not rounded to the correct decimal)

5 0

3 years ago

Boron (B) has two isotopes, boron-10 and boron-11. The atomic weight of boron is ?

suter [353]

Answer:

Approximately 10,5

Explanation:

The question is not really very specific, because it would need the percentages of those isotopes in the nature. As they are not shown, it should be the median of those two numbers.

atomic weight ≈ $\frac{10+11}{2}$ = 10,5

If you check a periodic table, you'll see it's actually 10,8, but that's because of the thing I told you at first (percentages missing).

Hope I could help.

8 0

3 years ago