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Kobotan [32]
3 years ago
10

This exercise uses the radioactive decay model.

Chemistry
1 answer:
Anna11 [10]3 years ago
3 0
For radioactive decay, we can relate current amount, initial amount, decay constant and time using:
N = No x exp(-λt)

Half-life = ln(2)/λ
λ = ln(2) / 5730
N/No = 80% = 0.8
0.8 = exp( -ln(2)/5730 x t)
t = 1844 years
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A chlorine atom has a diameter of 175 picometers (pm). Please write the diameter, in metered, in scientific notation.
Flauer [41]
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3 years ago
Explain how the mass of a single atom in an element (in amu), the mass of one mole of that element, and Avogadro’s number are re
Eva8 [605]

Answer: For 1 mole of a single atom it is equal to its molar mass. And a single atom, 1 mole is equal to the Avogadro's Number.

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4 0
3 years ago
Bromine has two isotopes 79Br and 81Br, whose masses (78.9183 and 80.9163 amu) and abundances (50.69% and 49.31%, respectively)
Reika [66]

Answer:

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Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

<u>For first isotope: </u>

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<u>For second isotope: </u>

% = 49.31 %

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Thus,  

Average\ atomic\ mass=\frac{50.69}{100}\times {78.9183}+\frac{49.31}{100}\times {80.9163}\ amu

Average\ atomic\ mass=40.0036+39.8998\ amu

<u>Average atomic mass = 79.9034 amu</u>

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3 years ago
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8 0
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