Triangle HIJ is dilated by a scale factor of 5 to form triangle H'I'J'. Side I'J' measures 75. What is the measure of side IJ?
1 answer:
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Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
( ) & (
)-
y - =
( x -
)
i.e. <em> y - 7= ( x- 1)</em>
<em> y - 7 = ( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
The measures of the angles of Δ DEF are 36° , 72° , 72°
Step-by-step explanation:
The sum of the measures of the interior angles in any triangle is 180°
In Δ DEF
The ratio between the measures of its interior angles is 2 : 4 : 4
To find the measure of each angle
1. Find the sum of the ratio between the measures of its angles
2. Divide 180° by the sum of the ratio
3. Multiply the quotient by each ratio
∵ The ratio between the measures of the angles of Δ DEF = 2 : 4 : 4
∴ The sum of the ratio = 2 + 4 + 4 = 10
→ m∠D : m∠E : m∠F : sum of the ratio
→ 2 : 4 : 4 : 10
→ ? : ? : ? : 180°
Divide 180 by 10, then multiply the quotient by the components of
the ratio to find the measure of each angle
∵ m∠D =
∴ m∠D = 36°
∵ m∠E =
∴ m∠D = 72°
∵ m∠F =
∴ m∠F = 72°
The measures of the angles of Δ DEF are 36° , 72° , 72°
Learn more:
You can learn more about the ratio in brainly.com/question/2707032
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