Answer:
D. f(x) is shifted up 1 unit to g(x).
Step-by-step explanation:
Just let's look at the y-intercept of each function.
f(0) = 0
g(0) = 1
Also remember that a vertical shift of N units is written as:
g(x) = f(x) + N
where if N is positive, the shift is upwards, and if N is negative, the shift is downwards.
then we can write, for the particular value x = 0
g(0) = f(0) + N
replacing the values
1 = 0 + N
1 = N
Then N is positive, so we have a shift up of one unit.
The correct option is:
D. f(x) is shifted up 1 unit to g(x).
Answer:
Advance=15$
Same-day=20$
Step-by-step explanation:
Advance=15 Same-day=20
15*35=525
20*30=600
525+600=1125
Step-by-step explanation:
For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,
b^2 - 4ac must be positive.
b^2 - 4ac > 0
(k - 3)^2 - 4(3 - 2k) > 0
k^2 - 6k + 9 - 12 + 8k > 0
k^2 + 2k - 3 > 0
1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational. Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. <span>√4 = 2, rational.</span>
√4 + <span>√16 = 2 + 4 = 6. rational
</span>√5 + √36...<span> irrational
</span>√9 + <span>√24... irrational
</span>2 × <span>√4 = 2 × 2 = 4. rational
</span>√49 × <span>√81 = 7 × 9 = 63. rational
</span>3√12... irrational
2.


3.


4.
![n^\frac1x=\sqrt[x]n](https://tex.z-dn.net/?f=n%5E%5Cfrac1x%3D%5Csqrt%5Bx%5Dn)
![\sqrt[3]{m^2n^5}=m^{\frac23}n^{\frac53}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E2n%5E5%7D%3Dm%5E%7B%5Cfrac23%7Dn%5E%7B%5Cfrac53%7D)
5.


A, since neither 3 nor 12 is a square but we end up with 6.
I believe that the smallest number of students Jimmy can measure is 223, and I know this is right because one of my teachers had us do this probem and she said this was it.