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2 years ago

NO LINKS OR ELSE YOU'LL BE REPORTED!Only answer if you're very good at Math.No guessing please.

Mathematics

1 answer:

vlada-n [284]2 years ago

3 0

Answer: D) 154 degrees clockwise about point A

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Explanation:

We have n = 7 sides here, so this is a heptagon.

Assuming this is a regular heptagon, then we can say that 360/n = 360/7 = 51.4285714285714 is the angle in which we can rotate the figure to have it map onto itself.

What does that mean? It means that if we were to apply this rotation, then the "before" and "after" (aka preimage and image) will be identical.

The angle value 51.4285714285714 rounds to 51, and unfortunately none of the answer choices come closer to this.

But we can scale things up. Instead of doing 1 rotation, we can do 3 rotations of 51.4285714285714 degrees each to get 3*51.4285714285714 = 154.285714285714

The value then rounds to 154 degrees. This can happen clockwise or counterclockwise.

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Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

Samantha has a rectangular shaped fish tank in her room. The tank has a height of 2.6 ft, a width of 2.1 ft, and a length of 3.9

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Answer: the BEST approximation of the amount of water her fish tank can hold is 21ft^3

Step-by-step explanation:

The shape of Samantha's fish tank is rectangular. The volume of the rectangular fish tank would be expressed as LWH

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L represents length of the tank

W represents the width of the tank.

H represents the height of the tank.

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3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

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