Answer:
Check below
Step-by-step explanation:
1) Check the rectangle below with a line k, the axis of rotation in the center of the figure.
2) Since it has a perimeter of 32 units and it is to be rotated about the line, the solid to be created it is a cylinder. As you can see below.
3) Let's calculate its radius, based on the information given, i.e. the perimeter:
Since the line of rotation is the center, and the radius is half the line segment of the basis, then the radius is 5.
Answer:
Area of circle A =113.14 mm²
Area of circle b = 314.29 mm²
Area of circle C = 452.57 mm²
Area of circle A = 254.57 mm²
2.25 times
Step-by-step explanation:
Area of a circle = nr²
where n = 22/7
r = radius
Circle A's radius = 6mm
Circle B's radius = 6mm + 4mm = 10mm
Circle C's radius = 10mm + 2mm = 12mm
Circle D's radius = 12mm - 3mm = 9mm
Area of circle A = (22/7) x 6² = 113.14 mm²
Area of circle b = (22/7) x 10² = 314.29 mm²
Area of circle C = (22/7) x 12² = 452.57 mm²
Area of circle A = (22/7) x 9² = 254.57 mm²
Number of times the area of circle D is greater than that circle A = Area of circle D / Area of circle A
254.57 mm² / 113.14 mm² = 2.25 times
The answer is none. There are no solutions
They are $0.2 each
10/50=.20
