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torisob [31]
3 years ago
14

10 points help me please

Mathematics
2 answers:
adell [148]3 years ago
8 0

Answer:

charge your computer <3

Step-by-step explanation:

but put the dot on the 2 on the y-axis

nevsk [136]3 years ago
6 0

Answer:

(0,2) and (-3,1)

Step-by-step explanation:

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The white Christmas tree is 7.55m tall.the green Christmas tree is twice as tall as the white Christmas tree which is 0.454m tal
Alja [10]

The white Christmas tree is 7.55m

Green Christmas tree is twice as tall as white Christmas tree: 7.55 * 2 = 15.1m

High golden Christmas tree: 15.1m - 0.454m = 14.646m

The total height of 3 Christmas trees is: 7.55m + 15.1m + 14.646m = 37.296m

Choose: A 37.296m

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3 years ago
in the apex republic, 8% of the population was unemployed in may of 2006. if there were 176,000,000 people willing to work in th
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Take 176000000 and multiply by 8% (or 0.08)

176000000 * 0.08 = 14,080,000 unemployed
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4 years ago
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A class has 10 boys and 12 girls. in how many ways can a committee of four be selected if the committee can have at most two gir
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5 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
Can someone help me with this :(?
serg [7]

= ( x + 2 )°

= (7y)°

<h2>#<em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>learning</u></em></h2>

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2 years ago
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