Answer:
800
Step-by-step explanation:
Answer:
it would be 3.28125
Step-by-step explanation:
do base times height to get the area
Answer:
5) 27/70
6) 90
Step-by-step explanation:
5) The first step in this problem is to figure out the amount of total spins. To do so, add up all of the numbers in the column "Frequency".
18 + 15 + 27 + 10 = 70.
Now, look at the amount of times the spinner landed on green. This is 27 times. So, the ratio of green spins to total spins is 27:70, or 27 out of 70 spins. Converting this to a fraction, we get the final answer, 27/70.
6) To solve this problem, we have to first do the same steps as the previous problem, but with the color red. There are 70 total spins, and 18 red spins. Therefore, the ratio is 18:70. However, this problem wants the total number of spins to be 350. In other words, 70 needs to become 350. To do this, multiply each side of the ratio by 5. The ratio becomes 90:350. Using this ratio, we can determine that a solid prediction is 90 red spins out of 350 total spins.
The trig function sine, often abbreviated as "sin" (pronounced the same way as "sine"), is essentially the ratio or fraction of the opposite side and the hypotenuse. See the attached image for a reference.
The leg opposite angle B is side AC. Note how B is not present in the sequence "AC". Visually, we are as far away as possible from point B. This side is 16 units long. So AC = 16
The hypotenuse is the longest side of the right triangle. Always always always. This longest side is opposite the largest angle (90 degrees). Therefore the hypotenuse is BC = 17.46
In summary so far, we have,
opposite side = AC = 16
hypotenuse BC = 17.46
Let's use those values to compute sin(B)
sin(Angle) = opposite/hypotenuse
sin(B) = AC/BC
sin(B) = 16/17.46
sin(B) = 0.916 (this is approximate)
sin(B) =
0.92 (rounding to nearest hundredth)
This points to the
final answer of choice A) 0.92--------------------------------
Edit: Sorry nearly forgot about the reference image. I attached it just now.
The answer is C. hope this helps.