Yes this is because you are adding all the numbers
A = 2
b = 2
c = -4
"a" is greater than zero so the vertex is a minimum point and the graph is concave up.
The (x,y) point of the vertex is usually designated by the letters (h, k)
The "x" position (or "h") is calculated with this formula:
h = -b / 2a
h = -2 / 4
h = -1 / 2
"k" is calculated with this equation:
k = ah^2 + bh +c
k =(2*-1 / 2 * -1 / 2) + (2 * -1 / 2) + -4
k = (1 / 2) - 1 -4
k = -4.5
so the vertex is at point (-.5, -4.5)
Source:
http://www.1728.org/quadr3.htm
The answer
<span>1/(a+2) = 1/a + 1/2 this equation is equivalent to </span><span>1/(a+2) = 2+a / 2a, it means
</span>1x( <span>2a) = </span>(a+2) x(2+a) , 2a= (a+2)² =a²+4+4a, so we have a²+2a+4=0, and this last doesnt have any solution (there is no value of a verifying a²+2a+4=0)
so the answer is <span>A. no real values a.</span>
Answer:
C
Step-by-step explanation:
Exponential decay should be in this format A = Ao × e^(-kt)