F(x)=2x^2+2x-4 find vertex

1 answer:

4 0

A = 2
b = 2
c = -4
"a" is greater than zero so the vertex is a minimum point and the graph is concave up.
The (x,y) point of the vertex is usually designated by the letters (h, k)
The "x" position (or "h") is calculated with this formula:
h = -b / 2a
h = -2 / 4
h = -1 / 2

"k" is calculated with this equation:
k = ah^2 + bh +c
k =(2*-1 / 2 * -1 / 2) + (2 * -1 / 2) + -4
k = (1 / 2) - 1 -4
k = -4.5
so the vertex is at point (-.5, -4.5)

Source:
http://www.1728.org/quadr3.htm

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