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elena-14-01-66 [18.8K]
3 years ago
8

Two standard six-sided dice are rolled. Wnat is the probability the

Mathematics
1 answer:
sergey [27]3 years ago
4 0
When rolling two standard die there are 36 possibilities.
The smallest sum being 2 (rolling a 1,1) and the largest being 12 (rolling a (6,6).
Of that range, prime numbers are 2, 3, 5, 7, 11.
In the sums there are 1-2's, 2-3's, 4-5's, 6-7's, and 2-11's.
P(sum 2 is die prime) = 15/36 = 5/12
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A. 3/13<br><br> B. 10/39<br><br> C. 5/12<br><br> D. 8/13
ELEN [110]
The equation to find P(A and B) is P(A and B)= P(A) x P(B/A). P(B/A) stands for probability of B given A. First we need to find out the P(A). The P(A) is 8/13 because you have 13 marbles total and 8 white marbles. For P(B/A), it is 5/12. This is because there are 5 red marbles and given that A happened, there would only be 12 marbles left in the bag, leaving you with a 5/12 chance of getting a red marble. Now plug it in. 8/13 x 5/12 = 40/156, which simplifies down to 10/39. Thus, B is the answer.
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3 years ago
Find a cartesian equation for the curve and identify it. r = 10 tan(θ) sec(θ)
Vilka [71]
For a cartesian equation
x=r\cos\theta \ and \ y=r\sin\theta \\  \\ \cos\theta=\frac{x}{r} \ and \ \sin\theta=\frac{y}{r} \\  \\ \tan\theta=\frac{\sin\theta}{\cos\theta}=\frac{y}{r}\cdot\frac{r}{x}=\frac{y}{x} \\  \\ \sec\theta=\frac{1}{\cos\theta}=\frac{r}{x}

Given r = <span>10 tan(θ) sec(θ)
r=10\tan\theta\sec\theta=10\cdot\frac{y}{x}\cdot\frac{r}{x} \\  \\ \Rightarrow10y=x^2 \\  \\ \Rightarrow y= \frac{1}{10} x^2

Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).
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3 years ago
The coordinate grid below shows triangle ABC and its image after translation, triangle A'B'C':
svetlana [45]

Answer:

+6 B

Step-by-step explanation:

Which of the following completes the rule for this translation, (x, y) + (x + 6, )?

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Y=.25x is the only resonable answer

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