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eduard
3 years ago
7

How many moles of n are in 0.187 g of n2o?

Chemistry
2 answers:
Ainat [17]3 years ago
8 0

We know that the molar mass of N is 14 and O is 16, therefore the molar mass of N2O is:

molar mass N2O = 14 * 2 + 16 = 44 g/mol

 

The number of moles:

moles N2O = 0.187 / 44

moles N2O = 0.00425 mol

 

There are 2 moles of N per 1 mole of N2O hence:

moles N = 0.00425mol * 2

<span>moles N = 0.0085 mol</span>

Andreyy893 years ago
6 0

(I haven't seen it done that simply before!! VERY VERY helpful! Will be using this method on my exam thursday!! Thanks again!) ^_^

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See explanation below

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This acid mechanism always involves carbocations, and positive charges, never negative because we are in acidic mediums.

In the first step, the lone pairs of the oxigen from the epoxide, substract one hydrogen of the reactant.

Second step, the lone pairs of the oxygen from the reactant, do a nucleophylic attack to the carbon of the epoxide. In this case, it will do it to the most substitued carbon.

Then, in the third step by acid base equilibrium, the hydrogen from the reactant that attacked, is substracted from the molecule by a molecule of water (We are in acid medium, therefore, there is traces of water) and the final structure is formed.

Check picture for mechanism:

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3 years ago
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7 0
3 years ago
Write the equilibrium-constant expression for the reactionA(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)in terms of [A], [
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3 0
3 years ago
1. Zinc reacts with steam according to the equation:
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Answer:

1) mass ZnO = 55.155 g

2) V SO2(g) = 18.289 L

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⇒ mol Zn = (41.6 g)(mol/61.38 g) = 0.678 mol Zn

⇒ mol ZnO = (0.678 mol Zn)(mol ZnO/mol Zn) = 0.678 mol ZnO

∴ mm ZnO = 81.38 g/mol

⇒ mass ZnO = (0.678 mol ZnO)(81.38 g/mol) = 55.155 g ZnO

2) S(s)  + O2(g)  →  SO2(g)

∴ mass S(s) = 24 g

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

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⇒ mol S(s) = (24 g)(mol/32.065 g) = 0.7485 mol S(s)

⇒ mol SO2(g) = (0.7485 mol S(s))(mol SO2(g)/mol S(s)) = 0.7485 mol SO2(g)

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⇒ V SO2(g) = ((0.082 atm.L/K.mol)(298 K)(0.7485 mol))/(1 atm)

⇒ V SO2(g) = 18.289 L SO2(g)

6 0
4 years ago
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