URGENT!
2 answers:
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Answer:
The concentration of NaCl = 0.3374 M
Explanation:
Given :
Molarity of AgNO₃ = 0.2503 M
Volume of AgNO₃ = 20.22 mL
The conversion of mL into L is shown below:
Thus, volume of the solution = 20.22×10⁻³ L
Molarity of a solution is the number of moles of solute present in 1 L of the solution.
The formula can be written for the calculation of moles as:
Thus,
The chemical reaction taking place:
According to reaction stoichiometry:
<u>1 mole</u> of AgNO₃ reacts with <u>1 mole</u> of NaCl
Thus,
5.0611×10⁻³ moles of AgNO₃ reacts with 5.0611×10⁻³ moles of NaCl
Thus, moles of NaCl required = 5.0611×10⁻³ moles
Volume of NaCl required = 15.00 mL
The conversion of mL into L is shown below:
Thus, volume of the solution = 15.00×10⁻³ L
Applying in the formula of molarity as:
<u>Thus, the concentration of NaCl = 0.3374 M</u>
Answer:
34,6g of (NH₄)₂SO₄
Explanation:
The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:
ΔT = kb×m
Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.
For the problem:
ΔT = 109,7°C-108,3°C = 1,4°C
kb = 1.07 °C kg/mol
Solving:
m = 1,31 mol/kg
As mass of X = 600g = 0,600kg:
1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:
0,785 moles of ions× = 0,262 moles of (NH₄)₂SO₄
As molar mass of (NH₄)₂SO₄ is 132,14g/mol:
0,262 moles of (NH₄)₂SO₄× = <em>34,6g of (NH₄)₂SO₄</em>
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I hope it helps!