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2 years ago

URGENT!

Chemistry

2 answers:

Law Incorporation [45]2 years ago

7 0

Answer:

Yea what they said^

Explanation:

Option 4 or D is correct

8.7 is your answer

MARK THE OTHER PERSON BRAINLIEST!!!

tensa zangetsu [6.8K]2 years ago

5 0

Answer:

Explanation:

A weak acid and a strong base will form a basic salt.

Option A is acidic, this pH would be found in salts formed from reactions between strong acids and weak bases.

B and C are neutral or close to neutral and as such will be formed from weak acids and weak bases, or strong acids and strong bases.

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The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c

netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is $4.58\times 10^{-3}M$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of oxygen gas

$C_2\text{ and }p_2$ are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used: 1 atm = 760 torr

$C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm$

Putting values in above equation, we get:

$\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M$

Hence, the solubility of oxygen gas at 628 torr is $4.58\times 10^{-3}M$

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2 years ago

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Solnce55 [7]

Answer:

oxygen

Explanation:

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Because they are salty

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inysia [295]

Answer:

Explanation:

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