Answer:
<h2>1.23 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>1.23 moles</h3>
Hope this helps you
Answer:
a) C4H6+2H2=C4H10
b) 4Na+CF4=4NaF+C
c) 2Na+2NH3=2NaNH2+H2
d) 2H202=2H2O+O2
Explanation:
Try and make sure there is the same number of reactants as products
PCl₅ reacts upon contact with water to launch hydrogen chloride and supply phosphorus oxides. the primary hydrolysis product is phosphorus oxychloride PCl₅ + H₂O ========> POCl₃ + 2HCl.
Phosphorus trichloride appears as a colorless or slightly yellow fuming liquid with a pungent and irritating odor resembling that of hydrochloric acid. Causes severe burns to skin, eyes and mucous membranes.
Divide the mass of the material through its molar mass. The molar mass of a substance is the mass in grams of 1 mole of that substance. This mass is given via the atomic weight of the chemical unit that makes up that substance in atomic mass units.
One mole is described as the amount of substance containing as many number one entities atoms, molecules, ions, electrons, radicals, and lots of others. As there are atoms in 12 grams of carbon - 12(6. 023×10²³. The mass of one mole of a substance equals to its relative molecular mass expressed in grams.
Learn more about phosphorous trichloride here:-brainly.com/question/2626850
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The first thing we need to remember is that:
We have 7.54g of CuCl2 so we need to express this amount in moles dividing by the molar mass of CuCl2.
This is:
And, also remember that 65.0mL equals 0.065L.
Now, replacing in the molarity equation:
Thus the answer is 0.862M.
Answer:
The equilibrium means that amount that are coming equals the amount that are going.
So the correct answers are
2. A person's income and expenses are equal every month.
3. The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.
