Question

1. Zinc reacts with steam according to the equation:

Answer 1

Answer:

1) mass ZnO = 55.155 g

2) V SO2(g) = 18.289 L

Explanation:

1) Zn + H2O  → ZnO + H2

∴ mass Zn = 41.6 g

∴ mm Zn = 65.38 g/mol

⇒ mol Zn = (41.6 g)(mol/61.38 g) = 0.678 mol Zn

⇒ mol ZnO = (0.678 mol Zn)(mol ZnO/mol Zn) = 0.678 mol ZnO

∴ mm ZnO = 81.38 g/mol

⇒ mass ZnO = (0.678 mol ZnO)(81.38 g/mol) = 55.155 g ZnO

2) S(s)  + O2(g)  →  SO2(g)

∴ mass S(s) = 24 g

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

∴ mm S(s) = 32.065 g/mol

⇒ mol S(s) = (24 g)(mol/32.065 g) = 0.7485 mol S(s)

⇒ mol SO2(g) = (0.7485 mol S(s))(mol SO2(g)/mol S(s)) = 0.7485 mol SO2(g)

ideal gas:

• PV = RTn

⇒ V SO2(g) = ((0.082 atm.L/K.mol)(298 K)(0.7485 mol))/(1 atm)

⇒ V SO2(g) = 18.289 L SO2(g)