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Darya [45]
3 years ago
7

Write the equilibrium-constant expression for the reactionA(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)in terms of [A], [

B], [C], and [D] as needed.Note that KcKc, which is sometimes symbolized as KeqKeq, denotes that the equilibrium constant is expressed using molar concentrations. For this question, KcKc means the same thing as KeqKeq.Kc=___________.
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

K_{c} = [\text{C}]^{2}[\text{[D]}

Explanation:

\rm A(s)+3B(l) \, \rightleftharpoons \, 2C(aq)+D(aq)

The general formula for an equilibrium constant expression is

K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}

Solids and liquids are not included in the equilibrium constant expression.

Thus, for this reaction,  

K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}

You might be interested in
Why do atoms fond bonds​
Setler [38]
They bond because they want to make their outer electron shells more stable

Hope this helps

Have a happy holidays
3 0
3 years ago
What is a neutralisation reaction? Give two examples.
ozzi

Explanation:

A neutralization is a type of double replacement reaction. a salt is the product of an acid-base reaction and is a much broader term then common table salt.

Example:-

(i) HCl + NaOH ---> NaCl + HOH

(ii) H2SO4 + 2NH4OH ---> (NH4)2SO4 + 2HOH.

7 0
3 years ago
What volume will be occupied by 5.00 mol of a gas at 25°C and 0.500<br> atm pressure?"
fomenos

Answer:

The volume will be occupied is 244, 36L.

Explanation:

We convert the unit of temperature to celsius into Kelvin, then use the ideal gas formula, solve for V (volume) and use the gas constant R =0.082 l atm / K mol:

0°C=273K  25°C= 273 + 25=298K

PV=nRT ---> V=nRT/P

V= 5,00 mol x 0,082 l atm/ K mol x 298 K/0,500 atm

<em>V=244,36L</em>

4 0
3 years ago
Acenapthalene has the empirical formula C6H5. A solution of 0.515 g of acenapthalene in 15.0 g CHCl3 boils at 62.5oC. The normal
german

Answer:

The molecular formula of an ascenapthalene is C_{12}H_{10}

Explanation:

\Delta T_b=K_b\times m

\Delta T_b=K_b\times \frac{\text{Mass of acenapthalene}}{\text{Molar mass of acenapthalene}\times \text{Mass of chloroform in Kg}}

where,

\Delta T_f =Elevation in boiling point = (62.5-61.7)^oC=0.8^oC

Mass of acenapthalene = 0.515 g

Mass of CHCl_3 = 15.0 g = 0.015 kg (1 kg = 1000 g)

K_b = boiling point constant = 3.63 °C/m

m = molality

Now put all the given values in this formula, we get

0.8^0C=3.67 ^oC/m\times \frac{0.515}{\text{Molar mass of acenapthalene}\times 0.015kg}

\text{Molar mass of acenapthalene}=155.7875 g/mol

Let the molecule formula of the Acenapthalene be C_{6n]H_{5n}

6n\times 12 g/mol+5n\times 1 g/mol=155.7875 g/mol

n = 2.0

The molecular formula of an ascenapthalene is C_{12}H_{10}

4 0
3 years ago
8. What is the name of this compound?
olga2289 [7]

Answer:

tert-butyl bromide

Explanation:

sec-butyl bromide

CH3 -CH-CH2-CH3

         Br

tert-butyl bromide

       CH3

CH3-C- Br

       CH3

isopropyl bromide

       CH3

CH3-CH-Br

isobutyl bromide

       CH3

CH3-CH-CH2-Br

6 0
3 years ago
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