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Darya [45]
3 years ago
7

Write the equilibrium-constant expression for the reactionA(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)in terms of [A], [

B], [C], and [D] as needed.Note that KcKc, which is sometimes symbolized as KeqKeq, denotes that the equilibrium constant is expressed using molar concentrations. For this question, KcKc means the same thing as KeqKeq.Kc=___________.
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

K_{c} = [\text{C}]^{2}[\text{[D]}

Explanation:

\rm A(s)+3B(l) \, \rightleftharpoons \, 2C(aq)+D(aq)

The general formula for an equilibrium constant expression is

K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}

Solids and liquids are not included in the equilibrium constant expression.

Thus, for this reaction,  

K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}

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A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
dsp73

Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
Find the average speed of a person who swims 105 m in 70 s
spin [16.1K]

Answer:

v = 1.5 m/s

Explanation:

Given that,

Distance covered by a person, d = 105 m

Time taken, t = 70 s

We need to find the average speed of the person. We know that the average speed is given by :

v=\dfrac{d}{t}\\\\v=\dfrac{105\ m}{70\ s}\\\\v=1.5\ m/s

So, the average speed of the person is equal to 1.5 m/s.

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3 years ago
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Answer:

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b. +3

c. -1

Explanation:

The typical oxidation states can be determined from the periodic table based on the number of valence electrons an atom has.

a. Calcium belongs to group 2A, meaning it has 2 valence electrons and, therefore, would have an oxidation state of +2 in compounds.

b. Aluminum is in group 3A, meaning it has 3 valence electrons and would have an oxidation state of +3 in compounds when the 3 electrons are lost.

c. Fluorine would become fluorine if it gained 1 additional electron to achieve an octet, so its oxidation state would be -1.

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