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Setler [38]
3 years ago
8

Let W be the union of the and quadrants in the​ xy-plane. That​ is, let . Complete parts a and b below. a. If u is in W and c is

any​ scalar, is cu in​ W? Why? A. If u is in​ W, then the vector cuc is in W because c0 since . B. If u is in​ W, then the vector cuc is not in W because c0 in some cases. C. If u is in​ W, then the vector cuc is in W because since . Your answer is correct. b. Find specific vectors u and v in W such that uv is not in W. This is enough to show that W is not a vector space. Two vectors in​ W, u and v​, for which uv is not in W are nothing. ​(Use a comma to separate answers as​ needed.)
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer:

hello your question is incomplete attached below is the complete question

A) xy ≥ 0, (cx )(cy) = c^2(xy) ≥ 0

B) U + V is not in W

Step-by-step explanation:

attached below is the detailed solution

A) since xy ≥ 0, (cx )(cy) = c^2(xy) ≥ 0

B )  U + V is not in W

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I have no idea what to do
tekilochka [14]

Answer: Y=-5x+30

Step-by-step explanation:

First, you have to find the slope of graph so you find the rise over run Y/X. Since the X values are being measured by 1’s, and the Y values are being measure by 5’s, your slope would be -5 (not 5 as the graph line is decreasing therefore it is negative). To find b, you find the Y intercept of the graph (where Y is when X=0) and in this case, the y intercept is 30. So the equation that describes what is occurring in the graph is Y=-5x+30 as a linear equation is written as Y=mx+b. You can check If the equation is correct by substituting the x and y values of a specific coordinate point on the graph. For example: 25= -5(1)+30. This gives you 25=25 so the equation is correct.

8 0
3 years ago
What are the first 3 common multiples of 3 and 5
marshall27 [118]
<span>The least common multiple is the smallest number that is divisible by each of the numbers being considered. Example: While 15, 30, 45, 60, 75, ... are all commonmultiplies of 3 and 5, 15 is the smallest number divisible by both 3 and 5. It is the leastcommon multiple.</span>
5 0
3 years ago
Read 2 more answers
Problemas de razonamiento división de números decimales. Ayer Susana se fue de viaje a visitar a unos familiares. Recorrió 135,7
schepotkina [342]

Usando las relaciones entre velocidad, distancia y tiempo, se encuentra que ella condujo a una velocidad media de 90,5 km/h.

--------------------------

La <u>velocidad </u><u>es la distancia dividida por el tiempo</u>, por lo que:

v = \frac{d}{t}

  • Total de 135,75 km, o sea, d = 135,75
  • Llego en 1,5 horas, o sea, t = 1,5

La velocidad es:

v = \frac{d}{t} = \frac{135,75}{1,5}

División de decimales, o sea, seguimos multiplicando los números por 10 hasta que ninguno sea decimal:

v = \frac{135,75}{1,5} = \frac{1357,5}{15} = \frac{13575}{150} = 90,5

Ella condujo a una velocidad media de 90,5 km/h.

Un problema similar es dado en brainly.com/question/24558377

4 0
2 years ago
2. True False 6(10 + 5) - 6.10 + 6.5<br><img src="https://tex.z-dn.net/?f=10%20%2B%205%20-%206.10%20%2B%206.5%20%5Ctimes%206" id
Ostrovityanka [42]

Answer:

<h2>47.9</h2>

Step-by-step explanation:

10 + 5 - 6.10 + 6.5 \times 6 \\

Follow PEDMAS

10 + 5 - 6.10 + 39

15 - 6.10 + 39 \\ 15 + 39 - 6.10 \\ 54 - 6.10 \\  = 47.9

8 0
3 years ago
Read 2 more answers
Tim has m dollars . Rebecca has $6 dollars less than 1 over 10 times the number of dollars that Tim has which expression represe
grin007 [14]

y= 1/10x - 6

Which if you plug in 70 for x, y equals 1.

Rebecca has $1 and Tim has $70, together they have $71.

8 0
3 years ago
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