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Setler [38]
3 years ago
8

Let W be the union of the and quadrants in the​ xy-plane. That​ is, let . Complete parts a and b below. a. If u is in W and c is

any​ scalar, is cu in​ W? Why? A. If u is in​ W, then the vector cuc is in W because c0 since . B. If u is in​ W, then the vector cuc is not in W because c0 in some cases. C. If u is in​ W, then the vector cuc is in W because since . Your answer is correct. b. Find specific vectors u and v in W such that uv is not in W. This is enough to show that W is not a vector space. Two vectors in​ W, u and v​, for which uv is not in W are nothing. ​(Use a comma to separate answers as​ needed.)
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0

Answer:

hello your question is incomplete attached below is the complete question

A) xy ≥ 0, (cx )(cy) = c^2(xy) ≥ 0

B) U + V is not in W

Step-by-step explanation:

attached below is the detailed solution

A) since xy ≥ 0, (cx )(cy) = c^2(xy) ≥ 0

B )  U + V is not in W

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u />

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  1. Cross-multiply:                     \displaystyle 6(2x - 2) = 19(x - 12)
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  5. Isolate <em>x</em>:                               \displaystyle \frac{216}{7} = x
  6. Rewrite:                                \displaystyle x = \frac{216}{7}
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