Calculate the molarity of 0.300 mol of Na2S in 1.75 L of solution.
1 answer:
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Answer: Thus 0.724 mol of are needed to obtain 18.6 g of
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of are produced by = 1 mole of
Thus 1.09 moles of will be produced by =
of
But as yield of reaction is 75.6 %, the amount of needed is =
Thus 0.724 mol of are needed to obtain 18.6 g of