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Cerrena [4.2K]
2 years ago
5

What is the name of the compound with the chemical formula (NH4)2S?

Chemistry
1 answer:
ddd [48]2 years ago
3 0
NH₄⁺ - ammonium cation
S²⁻ - sulfide anion

(NH₄)₂S - ammonium sulfide
The answer is A.
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A 2.4L balloon filled with helium at room temperature 25oC is put into liquid nitrogen
Stels [109]

Answer:

V₂ = 0.62 L

Explanation:

Given data:

Initial volume = 2.4 L

Initial temperature = 25°C

Final temperature = -196°C

Final volume = ?

Solution:

Initial temperature = 25°C (25+273 = 298 K)

Final temperature = -196°C ( -196+273 = 77 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 2.4 L × 77 K / 298 k

V₂ = 184.8 L.K / 298 K

V₂ = 0.62 L

5 0
2 years ago
Sedimentary rocks form
grin007 [14]
Hello there!

Sedimentary rocks are formed due to layers so the answer is A.

Best wishes
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5 0
3 years ago
Analyze the role coefficients in a chemical reaction play in stoichiometry
kumpel [21]

Answer:

This is known as the coefficient factor

Explanation:The balanced equation makes it possible to convert information about one reactant or product to quantitative data about another element.

7 0
2 years ago
The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma
Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})}  \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}

By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

4 0
3 years ago
How might the eruption of a large volcano affect weather for years to come
netineya [11]
The ashes released from the volcano could lead to acid rain and ash clouds.
3 0
3 years ago
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