Answer:
w = 21
Step-by-step explanation:
i've done this kind of thing before a million times
The equation which represents exponential decay is y=
Given four equations : 1)y=
, 2) y=
, 3) y=
, 4) y=.
Equation is relationship between two or more variables expressed in equal to form. Equations of two variables look like ax+by=c. Exponential equation look like 
.
Decay means when x value increases ,the y value decreases.
We haveto put 3 values for x in the equations to check.
1)y=
put x=0,y=-3
put x=1, y=-1
put x=2, y=5
No,itdoes not represents exponential decay.
2) y=2
put x=0,y=2
put x=1, y=8
put x=2, y=32
No,it does not represents exponential decay.
3) y=
put x=0,y=0.5
put x=1, y=1.5
put x=2, y=4.5
No,it does not represents exponential decay.
4)y=6
put x=0,y=6
put x=1, y=2
put x=2, y=0.67
Yes ,it represents exponential decay.
Hence the equation which represents exponential decay is y=6.
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Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
