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miskamm [114]
3 years ago
15

Only known planet able to support life

Physics
1 answer:
Nataly [62]3 years ago
3 0
1 is the correct answer
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Consider a person sliding down a water slide at constant velocity. what are the forces acting on the person as they slide? are t
Andru [333]

Explanation :

When a person is sliding with constant velocity, the forces that are acting on him are :

(1) Weight, W = mg where g is acceleration due to gravity.

(2) Friction forces acting opposite to the direction of motion.

(3) Normal force.

The forces acting on the person is balanced because the person is sliding with constant velocity.

From figure it is clear that, friction force is balanced by w\ sin\theta and normal is balanced by w\ cos\theta.

4 0
3 years ago
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some animals communicate by emitting low frequency sound waves.When the animal emits a low frequency sound wave what is the resu
valentina_108 [34]

Pitch is way to relate a sound to its frequency. High frequencies have high pitches (think of a flute), and low frequencies have low pitches (think of a bass).
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7 0
3 years ago
what seems to happen to the one electron in the outer layer of sodium when it combines with chlorine to form sodium chloride?
Hunter-Best [27]
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3 0
11 months ago
A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete
NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}

From Rayleigh criteria

sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm

The focal length of the camera's lens is 300cm

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3 years ago
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