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miskamm [114]
3 years ago
15

Only known planet able to support life

Physics
1 answer:
Nataly [62]3 years ago
3 0
1 is the correct answer
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The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)
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Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

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q1 and q2 are the charges of the two objects

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In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

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Explanation:

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