Answer:
The intensity of the net electric field will:
Explanation:
Here we need first find the electric field due to the first charge at the midway point.
The electric field equation is given by:
Where:
- k is Coulomb's constant
- q(1) is 20.00 μC or 20*10⁻⁶ C
- d is the distance from q1 to the midpoint (d=10.0 cm)
So, we will have:
The direction of E1 is to the right of the midpoint.
Now, the second electric field is:
The direction of E2 is to the right of the midpoint because the second charge is negative.
Finally, the intensity of the net electric field will:
I hope it helps you!
Could be very slow since they’re basically going against the current which is hard so will be going slow
Answer:
50m/s.
Explanation:
Let's take acceleration as A and speed as S:
A = 5m/s²
S = A × 10s = 5 × 10 = 50m/s
The answer is 50m/s.
Answer:
The speed of the particle is 13767.35 m/s.
Explanation:
given the mass m = 6.67×10^-27 kg of particle and moving with a speed v. the momentum of the particle is given by P = m×v and the planck constant h = 6.63×10^-34 m^2×kg/s. the wavelength is λ = 7.22 pm ≈7.22×10^-12 m
The de Broglie wavelength is given by:
λ = h/P
λ = h/(m×v)
v = h/λ×m
= (6.63×10^-34)/[(7.22×10^-12)×(6.67×10^-27)]
= 13767.35 m/s
Therefore, the speed of the particle is 13767.35 m/s.
