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weqwewe [10]
2 years ago
9

A) what is average rate of change of f(x) over the interval from x=5 to x=9? (table shows values of f(x). graph shows function o

f g(x).)
table:
x: 4, 5, 6, 7, 8, 9, 10
F(x): -8, -4, 8, 10, 11, 14 ,18


b) Find the average rate of change of g(x) over the interval from x = 0.25 to x= 1. (Write answer as a simplified fraction. Show work)

c) if g(x) represents the height of a ball that was throw. up into the air, interpret your answer from part b) in terms of the real-world it represents.

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

The average rate of change of a function over the interval [a,b] is equal to \frac{f(b)-f(a)}{b-a}, hence:

\frac{f(b)-f(a)}{b-a}\\\\\frac{f(9)-f(5)}{9-5}\\\\\frac{14-(-4)}{9-5}\\ \\\frac{14+4}{4}\\ \\\frac{18}{4}\\ \\\frac{9}{2}

Therefore, the average rate of change of f(x) over the interval [5,9] is \frac{9}{2}.

<u>Part B</u>

Do the same thing as in Part A:

\frac{f(b)-f(a)}{b-a}\\ \\\frac{f(1)-f(0.25)}{1-0.25}\\ \\\frac{2-5}{0.75}\\ \\\frac{-3}{0.75}\\ \\-4

Therefore, the average rate of change of g(x) over the interval [0.25,1] is -4.

<u>Part C</u>

To interpret our answer from Part B in terms of the real world it represents, we say that between 0.25 seconds and 1 second, the ball falls at a rate of 4 feet per second (since our average rate of change is negative).

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