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wel
2 years ago
12

Write 1011.1012 in normalized exponential form.

Mathematics
1 answer:
just olya [345]2 years ago
3 0

1011.101_2 in a normalized exponential form is written as 0.1011101 \times 2 ^4

<u>Given the following data:</u>

  • 1011.101_2

<h3>A normalized exponential form.</h3>

In Computer technology, binary numbers like decimal numbers in mathematics can be written in an exponential form and it involves the use of powers of two (2) rather than powers of ten (10).

Additionally, all non-zero binary numbers have a unique normalized exponential form and their binary point must always appear before the first one (1) bit, which yields a unique integer (exponent) and a unique mantissa respectively.

Thus, the normalized exponential form for the given binary number is written as follows:

1011.101_2 = 0.1011101 \times 2 ^4

<u>Note:</u>

  • Exponent = 4.
  • Mantissa = 0.1011101.

Read more on binary numbers here: brainly.com/question/5381889

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Answer:

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Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

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Of course, anywhere along the chain of equal signs the expressions are equivalent.

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3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

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4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

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