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2 years ago

1. Write an algebraic expression to represent each verbal phrase.

Mathematics

1 answer:

pantera1 [17]2 years ago

8 0

Answer:

a) p+2

b) 193x+19

c) 18 - a÷b

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Find the circumference of the circle whose diameter is 210cm

Lynna [10]

Circumference=2πr
=2*3.14*105
=659.4cm

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2 years ago

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The time X it takes Hattan to drive to work on a randomly selected day follows a distribution that is approximately Normal with

alexdok [17]

Answer:

Shape: Approximately Normal

Center: 20 minutes

Variability: 6.5 minutes.

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2 years ago

Given f(x)=3x+4. Determine the value of x if f(x)=21 to the nearest tenth.

ella [17]

Answer:

5.7

Step-by-step explanation:

3x+4 = 21

3x = 17

x = 5.666667 = 5.7

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2 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

9 months ago

At $13.35 per pound, what is the value of 4 pounds of crab legs

Dmitry_Shevchenko [17]

$53.40 is 4lb of crab legs
Bro you just gotta multiply $13.35x4=$53.40

7 0

2 years ago

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