Answer:
a) y = 6x - 3
b) 1/3y = 2x -1
The first thing you need to do is isolate (y) in the second equation
3 x (1/3y) = 3 x (2x - 1)
y =6x - 3
After isolating (y) in equation b they end up being the same.
Graphing:
In order to graph this, you have to make the first point at (0, -3) since this is the Y-intercept of the equation.
In order to graph the other points, you must move 6 units up and 1 unit to the right. Or vise versa If you need a visual I'll gladly link one.
It’s b because it’s -85 f so the planet is colder
Answer:
See below
Step-by-step explanation:
we have f(x) = -(x-7) + 3
and we want to find f(4)
essentially, f(4) means that the input is 4 and to find the output we plug in the value of the input where ever x is and evaluate.
So for f(x) = -(x-7) + 3
To find f(4) we replace all x's with 4
f(4) = -(4-7) + 3
we now evaluate
==> subtract 7 from 4
f(4) = -(-3) + 3
==> apply two negative rule ( basically if there are two negative signs they cancel out and the number turn positive )
f(4) = 3 + 3
==> add 3 and 3
f(4) = 6
The numbers that are 0.6 unit from 1.3 on the number line are 0.7 and 1.9
<h3>How to determine the
numbers that are 0.6 unit from 1.3 on the
number line?</h3>
The number is given as:
Number = 1.3
The distance is given as:
Distance = 0.6
The numbers that are 0.6 unit from 1.3 on the number line are represented as:
Number = 1.3 ± 0.6
Expand
Number = (1.3 - 0.6, 1.3 + 0.6)
Evaluate
Number = (0.7, 1.9)
Hence, the numbers that are 0.6 unit from 1.3 on the number line are 0.7 and 1.9
Read more about number lines at:
brainly.com/question/4727909
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