In 2.5 mole SO42−, there are

What happens when a covalent bond vs. an ionic bond is formed?

Bas_tet [7]

Explanation:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. ... A covalent bond involves a pair of electrons being shared between atoms. Atoms form covalent bonds in order to reach a more stable state.

4 0

3 years ago

A hydrocarbon is burnt completely to give 3.447g of

goblinko [34]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=3.447g$

Mass of $H_2O=1.647g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 3.447 g of carbon dioxide, $\frac{12}{44}\times 3.447=0.940g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.647 g of water, $\frac{2}{18}\times 1.647=0.183g$ of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.940g}{12g/mole}=0.0783moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.183g}{1g/mole}=0.183moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0783 moles.

For Carbon = $\frac{0.0783}{0.0783}=1$

For Hydrogen = $\frac{0.183}{0.0783}=2.34\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is $CH_2$

8 0

4 years ago

When 14 cal of heat are added to 12g of a liquid its temperature rises from 10.4 C to 12.7 C. What is the specific heat of the l

Zina [86]

Answer:

0.51 cal/g.°C

Explanation:

Step 1: Given data

Added energy in the form of heat (Q): 14 cal

Mass of the liquid (m): 12 g

Initial temperature: 10.4 °C

Final temperature: 12.7 °C

Step 2: Calculate the temperature change

ΔT = 12.7 °C - 10.4 °C = 2.3 °C

Step 3: Calculate the specific heat of the liquid (c)

We will use the following expression.

c = Q / m × ΔT

c = 14 cal / 12 g × 2.3 °C = 0.51 cal/g.°C

6 0

3 years ago

At a certain temperature the rate of this reaction is second order in with a rate constant of Suppose a vessel contains at a con

grigory [225]

Answer: The given question is incomplete. The complete question is:

At a certain temperature the rate of this reaction is second order in $NH_4OH$ with a rate constant of $34.1M^{-1}s^{-1}$ . $NH_4OH(aq)\rightarrow NH_3(aq)+H_2O(aq)$

Suppose a vessel contains $NH_4OH$ at a concentration of 0.100 M Calculate how long it takes for the concentration of $NH_4OH$ to decrease to 0.0240 M. You may assume no other reaction is important. Round your answer to 2 significant digits.

Answer: It takes 0.93 seconds for the concentration $NH_4OH$ to decrease to 0.0240 M.

Explanation:

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$