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konstantin123 [22]
3 years ago
9

Draw this image below. It shows one ton of feathers and one ton of bricks a. Compare the mass of the two substances:

Chemistry
1 answer:
bogdanovich [222]3 years ago
8 0

I don't understand the question

Can you elaborate further

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In nature, 1.07% of the atoms in a carbon sample are C-13 atoms. Show a numerical setup for calculating the number of C-13 atoms
Vera_Pavlovna [14]
If we let x be the number of sample which contains the atoms of carbon (C). Given that according to study, the amount of atoms in carbon sample that are C-13 atoms is 1.07%, the mathematical set-up that would represent the sample is,
                               = (0.0107)(C)

6 0
3 years ago
Dung dịch nào sau đây chỉ chứa các ion (bỏ qua sự điện li của nước, các chất điện li mạnh phân li hoàn toàn)?
LenKa [72]

Answer:

Dung dịch nào sau đây chỉ chứa các ion (bỏ qua sự điện li của nước, các chất điện li mạnh phân li hoàn toàn)?

A. HBr, Na2S, Mg(OH)2, Na2CO3.

B. H2SO4, NaOH, NaCl, HF.

C. HNO3, H2SO4, KOH, K2SiO3.

D. Ca(OH)2, KOH, CH3COOH, NaCl.

8 0
3 years ago
What part of the food chain is a mink?​
Tomtit [17]

Answer:

The minks are very high on the aquatic food chain. The mink is a carnivorous animal, which means it eats only meat.

Explanation:

5 0
3 years ago
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Suppose 20.8 g of sodium iodide is dissolved in 250. mL of a 0.70 M aqueous solution of silver nitrate. Calculate the final mola
gtnhenbr [62]

Answer:

[Ag+] = [NO3-] = 0.700M

0.555M = [Na+] = [I-]

Explanation:

To solve this question we need to find the moles of sodium iodide, NaI, using its molar mass -. With the moles and the volume we can find the molarity of Na+ and I-. The molarity of the ions of silver nitrate, AgNO3 doesn't change because we are assuming the volume doesn't change:

<em>Molarity Ag⁺ = Molarity NO₃⁻ = 0.700M</em>

<em>Moles NaI -Molar mass: 149.89g/mol-</em>

20.8g NaI * (1mol/149.89g) = 0.0139 moles NaI

<em>Molarity:</em>

0.0139 moles NaI / 0.250L = <em>0.555M = [Na+] = [I-]</em>

7 0
3 years ago
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B.) Index of refraction of the second medium is higher
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