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3 years ago

What is 9.562359123571283578 rounded to the nearest hundredth?

2 answers:

4 0

9.56 because you don't round up when two is the next number. (The hundredths place is the second number after the decimal, where the 6 is in the original number.)

guajiro [1.7K]3 years ago

4 0

The correct answer would be 9.56

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What is the value for f(x)4^2x -100 when x=2 ?<br><br> (the ^2x is a exponent)

PolarNik [594]

Answer:

156

Step-by-step explanation:

f(x)= 4^(2x) -100

Let x =2

f(2)= 4^(2*2) -100

= 4^4 - 100

= 256 -100

= 156

3 0

2 years ago

Gizela teaches 5 yoga classes that are each 3/4 hour. Use the drop down menu to complete the equation below to find the number o

Assoli18 [71]

Answer:

3.75 hours (3 hours and 45 minutes)

Step-by-step explanation:

5 times 3/4 = 3.75

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3 years ago

Choose an absolute value inequality for the situation with the given tolerance.

Serjik [45]

Answer

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3 years ago

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Vera_Pavlovna [14]

The room is not in shape of a square but a rectangle.

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3 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago