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4 years ago

What is 9.562359123571283578 rounded to the nearest hundredth?

2 answers:

4 0

9.56 because you don't round up when two is the next number. (The hundredths place is the second number after the decimal, where the 6 is in the original number.)

guajiro [1.7K]4 years ago

4 0

The correct answer would be 9.56

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Isaiah is starting his own gardening business. Isaiah thinks he can charge $15.50 per hour. If he knows he

Genrish500 [490]

Answer:

About $1627.5

Step-by-step explanation:

15.50 x 35 = 542.5

542.5 x 3 (the amount of weeks in a month) = $1627.5

7 0

3 years ago

What is the value of 2 thirds + 3 fourths

inn [45]

Step-by-step explanation:

⅔ + ¾

→ make the denominator equal of both the fraction

= 2/3 × 4/4 = 8/12

= 3/4 × 3/3 = 9/12

hence,

8/12 + 9/12

= 8 + 9/12 = 17/12

$\frac{17}{12} or \: 1 \frac{5}{12}$

hope this answer helps you dear...take care

3 0

3 years ago

Hii Help plzz anyone!!

natka813 [3]

Answer:

It's just addition and subtraction.

Step-by-step explanation:

1. $65,000

2. 66,000

3. 114,000

7 0

3 years ago

Read 2 more answers

Please help... no links

iris [78.8K]

If I get a uniform then I make the team.

4 0

3 years ago

A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The

Vladimir [108]

Using the Sine rule,

$\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}$ $\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}$

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

$A^0+P^0+B^0=180^0$ $\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}$

Using the side rule to find the length of wire BP,

$\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}$

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0

1 year ago