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3 years ago

Simplest form of -1 5/8 divided by 5 8/9

Mathematics

1 answer:

Crank3 years ago

7 0

Answer:

the answer is -117/424, hope this helps :)

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A cell-phone company has noticed that the probability of a customer experiencing a dropped call decreases as the customer approa

agasfer [191]

Answer:

the answer is 0.00221184

Step-by-step explanation:

as we can see 3rd term is product of first two terms

4th term is product of third and second term

5th term is the product of fourth and third term

the next term in the sequence which is the sixth term will be the product of fifth and fourth term

3 0

3 years ago

Read 2 more answers

Someone help me pls

kow [346]

Assuming the typewriter-looking words are the line names...
1. Line R
2. Line Q (Or R, but it is most likely Q)
3. Points E and F

Collinear Meaning: http://mathworld.wolfram.com/Collinear.html

5 0

4 years ago

Solve for x and y.

goldenfox [79]

Answer:

x= 15

y= 5

Step-by-step explanation:

it is a reflective opposite side exterior angle or line you are seeing.

The angle on the other side is a vertical angle meaning it is the same. Which leads to show that the measurements are the same as well.

6 0

3 years ago

Y=x.arctan(x)^1/2. find dy/dx. pls show steps

Whitepunk [10]

$y=x(\arctan x)^{1/2}$

Use the product rule first:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

Use the chain rule to compute the derivative of $(\arctan x)^{1/2}$ . Let $z=(\arctan x)^{1/2}$ and take $u=\arctan x$ , so that by the chain rule

$\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}$

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}$

$\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}$

So we have

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}$

You can rewrite this a bit by factoring $(\arctan x)^{-1/2}$ , just to make it look neater:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)$

3 0

3 years ago

Add d and 9.Then,divide by 3

Furkat [3]

Answer:

(d+9)/3

Step-by-step explanation:

Add d and 9

d+9

Then divide by 3

(d+9)/3

6 0

3 years ago